time.sleep()函数显然是语法无效的原因

时间:2016-06-20 08:45:28

标签: python time syntax

这是一个Python中的票务供应商的程序。 在我添加time.sleep函数之前,它工作正常。 这是我的代码:

    import time
    spaces = 61
    def init():
        global spaces
        if spaces > 1:
            print("Welcome to OCR's car park!")
            print("The number of spaces remaining is "+ str(spaces-1) +".")
            print("What are the last three letters on your number plate?")
            numplate = input()
            if len(numplate) != 3:
                print("These letters are invalid.")
                time.sleep(1)
                init()
            elif numplate.isalpha():
                print("It's £3.45 for a ticket. Enter how much money you want to insert. Type 'cancel' to cancel.")
        confirm = input()
        if confirm == "cancel":
            print("Payment cancelled.")
            time.sleep(3)
            init()
        if int(confirm) < 345:
            print("You don't have enough money.")
            time.sleep(1)
            init()
            print("£" +str(confirm)+ " inserted.")
            time.sleep(2)
        if float(confirm)> 345:
            print("Taking change...")
            time.sleep(3)
            confirm = float(confirm)-345
            print("Change due: £" +str(len(confirm[0]))+ "." +str(len(confirm[1]))+str(len(confirm[2]))     
        time.sleep(1)
        print("Printing ticket. Please wait.")
        time.sleep(5)
        print("Thank you for choosing OCR's car park!")
        spaces -= 1
        print("")
        print("")
        print("|-----|")
        print("| "+str(numplate.upper())+"|")
        print("|-----|")
        print("")
        print("")
        init()
    else:
        print("These letters are invalid.")
        time.sleep(1)
        init()
elif spaces < 2:
    print("No More Spaces.")
    init()

每次运行时,都会显示一个弹出式提示'invalid syntax',它始终指向time.sleep(1)功能。

1 个答案:

答案 0 :(得分:2)

错误发生在你的下一行。

print("Change due:£"str(len(confirm[0]))+"."+str(len(confirm[1]))+str(len(confirm[2]))

缺少一个右括号。只需添加一个右括号。