弹出窗口没有显示

Question

你能告诉我代码的问题是什么吗？

<script type="text/javascript">
    function PopupCenter(pageURL, title,w,h) 
            {
                var left = (screen.width/2)-(w/2);
                var top = (screen.height/2)-(h/2);
                var targetWin = window.open (pageURL, title, 'toolbar=no, location=no, directories=no, status=no, menubar=no, scrollbars=no, resizable=no, copyhistory=no, width='+w+', height='+h+', top='+top+', left='+left);
            } 
            </script>
            </head>


echo "<td><a href='#' onclick='PopupCenter('viewitem.php?Rid=".$row['refnumber']."','myPop1',1000,800)'>  View</a></td>";

Answer 1

尝试删除一个引用：

由此：

echo "<td><a href='#' onclick='PopupCenter('viewitem.php?Rid=".$row['refnumber']."','myPop1',1000,800)'>  View</a></td>";

对此：

echo "<td><a href='#' onclick=PopupCenter('viewitem.php?Rid=".$row['refnumber']."','myPop1',1000,800)>  View</a></td>";

希望它有效。