我需要找出带尾随空格的记录。我尝试使用Length(rtrim)
构建查询,但是它没有返回所需的记录。
e.g。
abc "
abc "
abc "
请协助
答案 0 :(得分:5)
我认为你走在了正确的轨道上。以下示例将返回第二个和第三个文本,但不返回第一个文本。
SELECT * FROM
(SELECT 'abc' AS text FROM DUAL
UNION ALL
SELECT 'abc ' AS text FROM DUAL
UNION ALL
SELECT 'abc ' AS text FROM DUAL)
WHERE LENGTH(RTRIM(text)) != LENGTH(text);
对于包含可能有尾随空格的文本的列YOURTABLE
的表YOURCOLUMN
:
SELECT * FROM
YOURTABLE
WHERE LENGTH(RTRIM(YOURCOLUMN)) != LENGTH(YOURCOLUMN);
如果您还有HORIZONTAL TAB
,LINE FEED
或CARRIAGE RETURN
,则可以使用TRANSLATE
函数将这些视为普通空格:
SELECT * FROM
(SELECT 'abc' AS text FROM DUAL
UNION ALL
SELECT 'abc' || CHR(09) AS text FROM DUAL
UNION ALL
SELECT 'abc' || CHR(10) AS text FROM DUAL
UNION ALL
SELECT 'abc' || CHR(13) AS text FROM DUAL
UNION ALL
SELECT 'abc ' AS text FROM DUAL)
WHERE LENGTH(RTRIM(TRANSLATE(text, CHR(09) || CHR(10) || CHR(13), ' '))) != LENGTH(text);