Python Plotly库启用plot graphs or networks。
以下代码（来自此link）是一个函数，它返回一个字典，其中包含要绘制的节点的不同属性：
def scatter_nodes(pos, labels=None, color=None, size=20, opacity=1):
# pos is the dict of node positions
# labels is a list of labels of len(pos), to be displayed when hovering the mouse over the nodes
# color is the color for nodes. When it is set as None the Plotly default color is used
# size is the size of the dots representing the nodes
#opacity is a value between [0,1] defining the node color opacity
L=len(pos)
trace = Scatter(x=[], y=[], mode='markers', marker=Marker(size=[]))
for k in range(L):
trace['x'].append(pos[k][0])
trace['y'].append(pos[k][1])
attrib=dict(name='', text=labels , hoverinfo='text', opacity=opacity) # a dict of Plotly node attributes
trace=dict(trace, **attrib)# concatenate the dict trace and attrib
trace['marker']['size']=size
trace['marker']['color']=color
return trace
行trace['marker']['color']=color为所有节点指定相同的颜色。
如果我用trace['marker']['color']=random.randint(500)替换此行，它将为每个节点提供随机颜色。
我希望每个节点都有一个字典预定的颜色，节点作为键，颜色作为值。
我该怎么办？
答案 0 :(得分：0)
简单回答：只需要将color定义为自动使用节点编制索引的颜色列表。