Question

我对此question提出了一个问题。

如果玩家属于多个团队怎么办？

我有这个

JSON

  "Players" : {
    "-YRHd4IjrjsBXx__B" : {
      "name" : "The best forward",
      "creationDate" : "2016-02-26 15:50:39",
      "teams" : {
         "-KAByPeIz4IjrjsBXx__B" : true,
         "-KEFPuCXcqOah_GJwsMCu" : true,
         "-KEwuQxvGpYTEJ7YQ58-l" : true,
         "-KKF8vPtf8J7cfqFh2PLm" : true
      },
    },
  etc...
  }

玩家-service.js

getPlayers: function(teamid) {
  var Players = {};
  var teamsIndex = ref.child('teams/' + teamid + '/players/');
  var playersIndex = ref.child('players/');
  teamsIndex.on('child_added', function(snapshot) {
    var playerKey = snapshot.key;
    playersIndex.child(playerKey).on('value', function(playersnap){
      $timeout(function() {
          console.log("key", playerKey);
          players[playerKey] = playersnap.val();
      });
    });
  });
  teamIndex.on('child_removed', function(snapshot) {
    $timeout(function(snapshot) {
      delete players[snapshot.key()];
    });
  });

  return players;
}

但它返回一个对象列表。我知道我可以查询/更改firebase中的数据结构并将其作为$ firebaseArray返回，我更喜欢使用angularfire。

Answer 1

您通常根据想要检索数据来构建数据。

从我的理解（纠正我，如果我错了）你想得到一个团队中的所有球员。为此，我将使用这种结构：

"Players": {
  "player1": {...},
  "player2": {...},
  "player3": {...}
},
"Teams': {
  "team1": {...},
  "team2": {...}
},
"TeamPlayers" : {
  "team1": {
    "player1": true,
    "player2": true
  },
  "team2": {
    "player1": true,
    "player3": true
  }
}

或使用数组

"TeamPlayers" : {
  "team1": [
    0: "player1",
    1: "player2"
  ]
}

接收数据多对多关系Firebase

1 个答案: