Question

我正在使用以下PHP脚本上传多个文件：

<?php

if(isset($_FILES['uploadfile'])){
    $total_files = count($_FILES['uploadfile']['name']);
    if( $total_files > 0){

        for($i=0; $i<$total_files; $i++) {

            $file_name = $_FILES['uploadfile']['name'][$i];
            $file_size = $_FILES['uploadfile']['size'][$i];
            $file_tmp  = $_FILES['uploadfile']['tmp_name'][$i];
            $file_type = $_FILES['uploadfile']['type'][$i]; 

            $upload_Path = "storage/".$file_name;

            //var_dump($file_size); 
            //die; 

            if($file_size > 8000000){
                echo ('Total upload size must be less than 8 MB.');
                die;
            }   

            if($file_tmp == ""){
                echo ('There is no file path.');    
                die;    
            }
            else{
                if(!file_exists($upload_Path)){
                    move_uploaded_file($file_tmp, $upload_Path);
                }
                else{
                    $name = pathinfo($file_name, PATHINFO_FILENAME);
                    $ext  = pathinfo($file_name, PATHINFO_EXTENSION);
                    $new_name = $name.rand().'.'.$ext;

                    $new_Path = "storage/".$new_name;
                    move_uploaded_file($file_tmp, $new_Path);
                }
            }
        }
    }
    die('File uploaded successfully!');
}
?>

但问题是，每当发生错误时，例如echo ('Total upload size must be less than 8 MB.');，它都不会使用ajax输出。但是，成功上传后，会显示File uploaded successfully!。

我的AJAX如下：

$.ajax({
                type:'POST',
                url: 'mupld.php',
                data: formdata,
                processData:false,
                contentType:false,
                success: function(response){
                    alert('Success: '+response);
                },
                error: function(xhr, status, error){
                    alert('Error: '+status+' '+error);
                }
            });

在进行var转储时，我没有得到任何高于8mb的上传输出但是低于我得到的

Success: <pre class='xdebug-var-dump' dir='ltr'><small>int</small> <font color='#4e9a06'>3283515</font>
</pre>

Answer 1

@Jeff Bucket是对的，所以我编辑了我的答案：

实际上，您应该在成功回调中处理这些错误。 error（）回调保留用于浏览器和服务器之间的连接刚刚中断的情况，并且error（）参数期望处理这种情况，例如典型的textStatus错误应该是'Not Found'或'Internal Server Error '，但没有'总上传大小必须小于8 MB。'。

你应该返回一个包含你可以在客户端使用的信息的数组，并在success（）中处理它，如：

尝试{

if(isset($_FILES['uploadfile'])){
    $total_files = count($_FILES['uploadfile']['name']);
    if( $total_files > 0){

        for($i=0; $i<$total_files; $i++) {

            $file_name = $_FILES['uploadfile']['name'][$i];
            $file_size = $_FILES['uploadfile']['size'][$i];
            $file_tmp  = $_FILES['uploadfile']['tmp_name'][$i];
            $file_type = $_FILES['uploadfile']['type'][$i];

            $upload_Path = "storage/".$file_name;

            //var_dump($file_size);
            //die;

            if($file_size > 8000000){
                echo json_encode( array('status' => 'failure'  , 'msg' => 'Total upload size must be less than 8 MB.')  );
                die();
            }

            if($file_tmp == ""){
                echo json_encode( array('status' => 'failure'  , 'msg' => 'There is no filepath.')  );
                die;
            }
            else{
                if(!file_exists($upload_Path)){
                    move_uploaded_file($file_tmp, $upload_Path);
                }
                else{
                    $name = pathinfo($file_name, PATHINFO_FILENAME);
                    $ext  = pathinfo($file_name, PATHINFO_EXTENSION);
                    $new_name = $name.rand().'.'.$ext;

                    $new_Path = "storage/".$new_name;
                    move_uploaded_file($file_tmp, $new_Path);
                }
            }
        }
    }
    echo json_encode( array('status' => 'success'  , 'msg' => 'File uploaded succesfully.')  );
    die();
}

else{

    echo json_encode(array("status" => "error" , "msg" => "No file was found when processing uploaded files" ) );
    die();
}


}
catch(Exception $ex){

echo json_encode(array('status' => 'error' , 'msg' => 'An unhandled exception raised: ' . $ex->getMessage() ) );
die();
}
finally{
    die();
}

然后在$ .ajax（）函数中：

$("#uploadfile").change(function(){ 
//submit the form here 
var files = $("#fileupload")[0]; 
var formdata = new FormData(files); 
$.ajax({ 
    type:'POST', 
    url: 'mupld.php', 
    data: formdata, 
    processData:false, 
    contentType:false, 
    success: function(response){ 

             response = JSON.parse(response);
             alert(response.msg);

        }, 
    error: function(xhr, textStatus, error){ 
        console.log('Error: '+textStatus+' '+error); 
    } 
});

如果您特别想在error（）回调中处理此问题，则应将php脚本的响应代码设置为500或任何自定义代码 - 使用header（）。

Ajax成功函数不输出Php脚本发送的文本

1 个答案: