Question

嗨，这是我在stackoverflow的第一篇文章，我正在用C创建一个骰子游戏，我很难在每轮后添加一个退出功能。一旦用户做出预测，游戏循环再次运行并重新调整4个新的骰子值。

我想要包含一个函数，询问玩家是想继续进行还是通过（y / n）输入退出。

下面是我的骰子游戏的代码

#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
#include <string.h>
#include <math.h>
#include <time.h>

int main ()
{
    while(1)
    {
        srand ( time(NULL) );
        int i;
        int DiceR[4]; // Dice Array
        char prediction; //prediction input for high low or equal


        while (1)
        {

          for (i=0; i<1; i++)
    {
        DiceR[0] = (rand()%6) + 1;
        printf("\n%d \n", DiceR[0]);

        DiceR[1] = (rand()%6) + 1;
        printf("%d \n", DiceR[1]);

        DiceR[2] = (rand()%6) + 1;
        printf("%d \n", DiceR[2]);

        DiceR[3] = (rand()%6) + 1;

    }

        printf("\nDo you think the next dice roll will be higher or lower than %d", DiceR[2]);
        printf("\nPlease enter L = Lower E = Equal H = higher or X = Exit:\t");
        scanf("\n%c", &prediction);

        switch(prediction)
    {
    case 'L' : case 'l':
        if (DiceR[3] < DiceR[2]) //Lower
            printf("\ncongrats DiceRoll 4 is %d\n", DiceR[3]); //win
        else
            printf("\nYou lose, the last roll was %d\n", DiceR[3]); //Lose
        break;
    case 'E' : case 'e':
        if (DiceR[3] == DiceR[2]) //Equal
            printf("\ncongrats DiceRoll 4 is %d\n", DiceR[3]); //win
        else
            printf("\nYou lose, the last roll was %d\n", DiceR[3]); //Lose
        break;
    case 'H' : case 'h':
        if (DiceR[3] > DiceR[2]) //Higher
            printf("\ncongrats DiceRoll 4 is %d\n", DiceR[3]); //win
        else
            printf("\nYou lose, the last roll was %d\n", DiceR[3]); //Lose
        break;

    default:
        printf("that value is not recognized");
        break;


    }



        }
    }
    }

Answer 1

您可能需要在第一个while之前添加一个标记，例如，bool running = true;，在您要退出的位置将其设置为false，然后在while中检查而不是无限循环。

Answer 2

您可以创建一个标志并使用条件(flag==true);来保持代码在用户需要时运行

Answer 3

我想包含一个询问玩家是否需要的功能通过（y / n）输入继续前进或退出。

在每次滚动开始时要求用户继续或停止的功能

int cont()
{
    char ch;
    printf("\n want to continue or stop? y/n : \n");
    scanf(" %c",&ch); //note a space before %c to consume white spaces
    if(ch=='y'||ch=='Y')
        return 0; //if yes i.e, 'y' return 0
    return 1; //else return 1
}

以这种方式检查每次掷骰开始时函数的返回值：

（按照评论理解）

//#include .......

int cont()
{
    char ch;
    printf("\n want to start/continue? y/n : \n");
    scanf(" %c",&ch);
    if(ch=='y'||ch=='Y')
        return 0;
    return 1;
}

int main ()
{
    int flag=0; //initialize flag with a value of zero

    while(1) //first while loop
    {
        //srand and other variables initialization

        while (1) //second while loop
        {    
          //don't use if(cont()) here....

          //for loop

          //printing and scanning prediction

            switch(prediction)
            {

             //all other cases........              

             case 'X': case 'x': //you seem to have forgotten mentioning this case :)
                 flag=1;
                 break;

             //default case
            }


            //use it here instead sso that you'd get it at the end of each turn 
            if(cont()) //function call : here you ask user for y/n input
            {
              //if user enter no i.e, 'n', then you enter the if block
               flag=1;
               break;
            }

            if (flag==1) //checking for flag; useful when user enters 'X'
            break; //break out of first while loop
        }

        if(flag==1) //checking for flag
            break; //break out of second while loop
    }

}

Answer 4

这是一个经过纠正的＆＃39;代码的版本。

请注意，将调用值打印到rand()可能不是最佳方式，尤其是当用户玩游戏一段时间并识别模式时

#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
//#include <string.h>
//#include <math.h>
#include <time.h>

#define NUM_OF_DICE (4)
#define MAX_DICE_VALUE (6)

int main ()
{
    srand ((unsigned) time(NULL) );
    int DiceR[ NUM_OF_DICE ]; // Dice Array
    char prediction; //prediction input for high low or equal


    while (1)
    {
        for( size_t i=0; i<NUM_OF_DICE; i++)
        {
            DiceR[i] = (rand()%MAX_DICE_VALUE) + 1;
            printf("\n%d \n", DiceR[i]);
        }

        printf("\nDo you think the next dice roll will be higher or lower than %d", DiceR[2]);
        printf("\nPlease enter L = Lower E = Equal H = higher or X = Exit:\t");

        if( 1 != scanf("\n%c", &prediction) )
        { // then scanf failed
            perror( "scanf for inputting prediction failed");
            exit( EXIT_FAILURE );
        }

        // implied else, scanf successful

        prediction = (char)toupper(prediction);

        if( 'X' == prediction )
        {
            return 0;
        }

        switch(prediction)
        {

            case 'L' :
                if (DiceR[3] < DiceR[2]) //Lower
                    printf("\ncongrats DiceRoll 4 is %d\n", DiceR[3]); //win
                else
                    printf("\nYou lose, the last roll was %d\n", DiceR[3]); //Lose
                break;

            case 'E' :
                if (DiceR[3] == DiceR[2]) //Equal
                    printf("\ncongrats DiceRoll 4 is %d\n", DiceR[3]); //win
                else
                    printf("\nYou lose, the last roll was %d\n", DiceR[3]); //Lose
                break;

            case 'H' :
                if (DiceR[3] > DiceR[2]) //Higher
                    printf("\ncongrats DiceRoll 4 is %d\n", DiceR[3]); //win
                else
                    printf("\nYou lose, the last roll was %d\n", DiceR[3]); //Lose
                break;

            default:
                printf("input must be 'L' or 'H' or 'E' or 'X'\n");
                break;
        } // end switch
    }
} // end function: main

退出C骰子游戏的功能

4 个答案: