Question

这是我从表中获得排名的代码，但我想用INNER JOIN连接另外两个表，但是当我使用INNER JOIN时Rank会改变..请帮我解决这个问题...

SELECT ex_studentid, ex_studentname, ex_subjid, ex_batchno, ex_examdate, 
ex_code, ex_marks, @curRank := @curRank + 1 AS rank 
FROM cp_exams p, (SELECT @curRank := 0) r ORDER BY  ex_marks DESC;

INNER JOIN代码

SELECT ex_studentid, ex_studentname, ex_subjid, ex_batchno, ex_examdate, ex_code,
ex_marks, @curRank := @curRank + 1 AS rank 
FROM cp_exams p INNER JOIN `cp_students` 
ON stu_studentID = ex_studentid, (SELECT @curRank := 0) r ORDER BY  ex_marks DESC;

-------------------我的Mysql表-----------------

CREATE TABLE `cp_exams` (
    `id` INT(11) NOT NULL AUTO_INCREMENT,
    `ex_studentid` INT(11) NOT NULL,
    `ex_studentname` VARCHAR(255) NULL DEFAULT NULL,
    `ex_subjid` INT(11) NULL DEFAULT NULL,
    `ex_batchno` VARCHAR(255) NULL DEFAULT NULL,
    `ex_examdate` DATE NULL DEFAULT NULL,
    `ex_code` INT(20) NULL DEFAULT NULL,
    `ex_marks` INT(11) NULL DEFAULT NULL,
    PRIMARY KEY (`id`)
)
COLLATE='latin1_swedish_ci'
ENGINE=MyISAM
AUTO_INCREMENT=29

我想用cp_exams连接这些表，并获得ex_marks的学生排名.....

CREATE TABLE `cp_students` (
    `stu_ID` INT(11) NOT NULL AUTO_INCREMENT,
    `stu_studentID` INT(11) UNSIGNED NOT NULL,
    `stu_regdate` DATE NOT NULL,
    `stu_studentname` VARCHAR(255) NOT NULL,
    `stu_address` VARCHAR(255) NULL DEFAULT NULL,
    `stu_sex` VARCHAR(45) NOT NULL,
    `stu_bday` DATE NULL DEFAULT NULL,
    `stu_con_home` VARCHAR(255) NULL DEFAULT NULL,
    `stu_con_mobile1` VARCHAR(255) NULL DEFAULT NULL,
    `stu_con_mobile2` VARCHAR(255) NULL DEFAULT NULL,
    `stu_email` VARCHAR(255) NULL DEFAULT NULL,
    `stu_notes` VARCHAR(255) NULL DEFAULT NULL COLLATE 'big5_chinese_ci',
    `stu_passGrade` VARCHAR(45) NULL DEFAULT NULL,
    `stu_image_name` VARCHAR(255) NULL DEFAULT NULL,
    `stu_nic` VARCHAR(45) NULL DEFAULT NULL,
    `stu_school` VARCHAR(255) NULL DEFAULT NULL,
    `stu_accesskey` INT(11) NULL DEFAULT NULL,
    PRIMARY KEY (`stu_ID`)
)
COLLATE='utf8_general_ci'
ENGINE=MyISAM
AUTO_INCREMENT=800
;


CREATE TABLE `cp_exams_list` (
    `id` INT(11) NOT NULL AUTO_INCREMENT,
    `ex_code` INT(20) NULL DEFAULT NULL,
    `ex_des` VARCHAR(255) NULL DEFAULT NULL,
    PRIMARY KEY (`id`)
)
COLLATE='utf8_general_ci'
ENGINE=MyISAM
AUTO_INCREMENT=4
;

mysql用INNER JOIN排名

0 个答案: