Question

我已经在我的CustomTweetTimelineListAdapter类上覆盖了OnClikListener以及示例并且工作正常但是当推文包含一个url时，未检测到链接上的点击并且调用适配器OnClicklistener操作，它可以进行单击链接打开URL而不是使适配器OnClickListener操作？

package client.tclient.com.client;

import android.content.Context;
import android.content.Intent;
import android.view.View;
import android.view.ViewGroup;
import android.widget.Adapter;

import com.twitter.sdk.android.core.models.Tweet;
import com.twitter.sdk.android.tweetui.Timeline;
import com.twitter.sdk.android.tweetui.TweetTimelineListAdapter;

/**
 * Created by alvaro on 13/06/16.
 */
public class CustomTweetTimelineListAdapter extends TweetTimelineListAdapter implements Adapter{

    private Context context;
    /**
     * Constructs a TweetTimelineListAdapter for the given Tweet Timeline.
     *
     * @param context  the context for row views.
     * @param timeline a Timeline&lt;Tweet&gt; providing access to Tweet data items.
     * @throws IllegalArgumentException if timeline is null
     */
    public CustomTweetTimelineListAdapter(Context context, Timeline<Tweet> timeline) {
        super(context, timeline);
        this.context = context;
    }

    @Override
    public View getView(final int position, View convertView, ViewGroup parent) {
        View view = super.getView(position, convertView, parent);

        //disable subviews
        if(view instanceof ViewGroup){
            disableViewAndSubViews((ViewGroup) view);
        }

        //enable root view and attach custom listener
        view.setEnabled(true);
        view.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                Long tweetId = getItemId(position);
                Intent intent = new Intent(context,TweetActivity.class);
                intent.putExtra("TWEET_ID", tweetId);
                context.startActivity(intent);
            }
        });
        return view;
    }
    private void disableViewAndSubViews(ViewGroup layout) {
        layout.setEnabled(false);
        for (int i = 0; i < layout.getChildCount(); i++) {
            View child = layout.getChildAt(i);
            if (child instanceof ViewGroup) {
                disableViewAndSubViews((ViewGroup) child);
            } else {
                child.setEnabled(false);
                child.setClickable(false);
                child.setLongClickable(false);
            }
        }
    }
}

Answer 1

您的视图应该包含链接的引用，假设它是TextView 并为该子视图定义一个监听器。

单击自定义适配器上的链接

1 个答案: