Question

          <!----  Database File  --->


      <?php

      defined('DB_SERVER') ? null : define("DB_SERVER","localhost");
      defined('DB_USER')   ? null : define("DB_USER", "faizy");
      defined('DB_PASS')   ? null : define("DB_PASS", "faizy");
      defined('DB_NAME')   ? null : define("DB_NAME", "photo_gallery");

      class MySQLDatabase {

          private $connection;

          function __construct() {
              $this->open_connection();
          }

          public function open_connection() {
              $this->connection = mysqli_connect(DB_SERVER, DB_USER, DB_PASS, DB_NAME);
              if(!$this->connection) {
                  die("Database connection Failed: " .mysqli_error($this->connection));
              }else {
                  $db_select = mysqli_select_db($this->connection, DB_NAME);
                  if(!$db_select) {
                     die("Database connection Failed: " .mysqli_error($this->connection)); 
                  }
              }
          }

          public function close_connection() {
              if(isset($this->connection)) {
                  mysqli_close($this->connection);
                  unset($this->connection);
              }
          }

          public function query($sql) {
              $result = mysqli_query($sql, $this->connection);
              $this->confirm_query($result);
              return $result;

          }


          private function confirm_query($result) {
              if(!$result) {
                   die("Database connection Failed: " .mysqli_error($this->connection)); 
              }
          }


      }

      $database = new MySQLDatabase();
      $database->close_connection();

      ?>

      <!----Config FIle which ---->

      <?php
          defined('DB_SERVER') ? null : define("DB_SERVER","localhost");
          defined('DB_USER')   ? null : define("DB_USER", "faizy");
          defined('DB_PASS')   ? null : define("DB_PASS", "faizy");
          defined('DB_NAME')   ? null : define("DB_NAME", "photo_gallery");
      ?>

      <!--index.html-->
      <body>
       <?php
       require_once '../includes/database.php';
       if(isset($database)){ echo "true"; } else { echo "false"; }
       echo "<br/>";
       echo $database->mysql_prep("It's Working <br />");

       $sql  = "INSERT INTO users (id, username,password,first_name,last_name) VALUES(1,'walifaizy','12345','wali','faizy')";
       $result = $database->query($sql);
       ?>
       </body>



        [![Below are the errors][1]][1]

当我在数据库中插入一些东西而不是这些警告和通知即将到来时，任何人都可以建议我如何解决这些错误，我因为这些警告和通知而陷入困境，我正在以正确的方式定义常量，一切都是正确的这些通知即将到来的原因

Answer 1

检查第38行...... mysqli_query（$ con，＆＃34;您的查询＆＃34;）。这是正确的语法。以这种格式编写代码

Answer 2

在数据库包含文件的末尾，您在打开数据库后立即关闭数据库：

$database = new MySQLDatabase();
$database->close_connection();

因此它没有连接。

php oop连接失败

2 个答案: