我有两个收藏 user
和 Type
。我希望发送标有 IsPreffered = TRUE
的电子邮件ID,我需要将 email.Type映射到Type.ID
{ "user" : [
{
"Name" : "B. Balamanigandan",
"Email": [
{
"Id": "bala@gmail.com",
"IsPreffered": true,
"Type": 1,
},
{
"Id": "mani@gmail.com",
"IsPreffered": false,
"Type": 2,
}
]}
]};
{
"Type": [
{
"ID": 1,
"Name": "Private"
},
{
"ID": 2,
"Name": "Home"
},
{
"ID": 3,
"Name": "Business"
},
]}
HTML源代码:
<span ng-repeat="email in collection.user[0].Email | filter: {IsPreffered : true} " ng-if="$last"> {{email.Id}}</span>
在这里,我需要指定类型&#34; 私有&#34;对于上面的HTML。如何将 user[0].Email.Type
映射到 Type.ID
并获取相应的 Type.Name
请使用不在JavaScript级别的HTML级别过滤条件。请帮助我。
答案 0 :(得分:1)
我建议在代码中而不是标记中进行,但如果需要,可以使用一种方法映射到Type:
<span
ng-repeat="email in collection.user[0].Email| filter: {IsPreffered : true} "
ng-if="$last">
Email : {{email.Id}} ,
<span ng-repeat="typename in typeCollection.Type|filter:{ID : email.Type}">
Type: {{typename.Name}}
</span>
</span>
其中typeCollection为:
$scope.typeCollection = {
"Type": [{
"ID": 1,
"Name": "Private"
}, {
"ID": 2,
"Name": "Home"
}, {
"ID": 3,
"Name": "Business"
}, ]
};
请注意,您需要在标记中再添加一次ng-repeat,因为过滤器适用于阵列。
编辑: 您也可以使用ng-init:
执行此操作<span
ng-repeat="email in collection.user[0].Email| filter: {IsPreffered : true} "
ng-if="$last">
Email : {{email.Id}} ,
<span ng-init="types = (typeCollection.Type|filter:{ID : email.Type})">
Type: {{types[0].Name}}
</span>
</span>
答案 1 :(得分:0)
for(var i = 0; i < Type.length ; i++)
{
if(user[0].Email.Type to Type[i].ID)
{
user[0].Email.TypeName = Type[i].ID;
}
};
HTML
<span ng-repeat="email in collection.user[0].Email | filter: {IsPreffered : true} " ng-if="$last">{{email.TypeName}} : {{email.Id}}</span>