Question

我想要＃34;还有另一个＆＃34;回调注册的东西。扩展公共基本事件类型的不同事件类型将触发相关的回调函数。

这是初稿或想法

#include <functional>
#include <iostream>
#include <unordered_map>

class BaseEvent 
{ 
public: 
    virtual ~BaseEvent() {}
};

class DerivedEvent_1 : public BaseEvent {};
class DerivedEvent_2 : public BaseEvent {};


// a container holding callback functions
std::unordered_map<size_t/*event*/, std::function<void(BaseEvent)>/*callback*/> _callbacks;


// register callback funtion associated with specific event
template<typename EVT>  
void registerCallback(std::function<void(EVT)> cb)
{
    std::cout << "store callback associated with event " << typeid(EVT).name() << " [" << typeid(EVT).hash_code() << "]" << std::endl;
    //_functions[ typeid(EVT).hash_code() ] = cb; // FIXME
}


// trigger callback function
void triggerCallback(const BaseEvent* e)
{
    std::cout << "trigger callback with event " << typeid(*e).name() << " [" << typeid(*e).hash_code() << "]" << std::endl;
    //_functions[ typeid(*e).hash_code() ] (*e); // FIXME
}

// callback function for DerivedEvent_1
void callback_1(DerivedEvent_1 event_1)
{
    std::cout << "callback_1 called" << std::endl;
}

// callback function for DerivedEvent_2
void callback_2(DerivedEvent_2 event_2)
{
    std::cout << "callback_2 called" << std::endl;
}


int main(int argc, char *argv[])
{
    registerCallback<DerivedEvent_1>( [](DerivedEvent_1 e) { callback_1(e); } );
    registerCallback<DerivedEvent_2>( [](DerivedEvent_2 e) { callback_2(e); } );


    DerivedEvent_1 e1;
    DerivedEvent_2 e2;

    triggerCallback(&e1);
    triggerCallback(&e2);

    return 1;
}

到目前为止没有真正的实施......

$ g++ -std=c++11 -o testStdFunction testStdFunvtion.cpp 
$ ./testStdFunction 
store callback associated with event 14DerivedEvent_1 [4527193776]
store callback associated with event 14DerivedEvent_2 [4527193680]
trigger callback with event 14DerivedEvent_1 [4527193776]
trigger callback with event 14DerivedEvent_2 [4527193680]

情况和问题是：

事件是类或结构，可以具有特定属性作为有效负载
我想保留回调函数（例如void callback_1（DerivedEvent_1 event_1），而不使用指针作为参数。原因：这些回调函数可能已存在于代码库中，我不想更改它或制作额外的包装器。
我怎样才能让_callbacks映射为具有不同签名的std :: function？即让_callbacks映射可以保存std :: function

目的是修复registerCallback和triggerCallback中的FIXME代码。所以在运行代码后它们会是这样的

$ g++ -std=c++11 -o testStdFunction testStdFunvtion.cpp 
$ ./testStdFunction 
store callback associated with event 14DerivedEvent_1 [4527193776]
store callback associated with event 14DerivedEvent_2 [4527193680]
trigger callback with event 14DerivedEvent_1 [4527193776]
callback_1 called
trigger callback with event 14DerivedEvent_2 [4527193680]
callback_2 called

Answer 1

您可以使用已擦除的包装以下代码准确打印OP在问题中发布的消息关键类是BaseWrapper和模板类Wrapper 此外，我稍微更改了代码周围的功能签名，以使其正常工作。

#include <functional>
#include <iostream>
#include <unordered_map>
#include<memory>
#include<utility>

class BaseEvent 
{ 
public: 
    virtual ~BaseEvent() {}
};

class DerivedEvent_1 : public BaseEvent {};
class DerivedEvent_2 : public BaseEvent {};

struct BaseWrapper {
    virtual void operator()(const BaseEvent *) = 0;
};

template<typename T>
struct Wrapper: BaseWrapper {
    std::function<void(T)> fn;
    void operator()(const BaseEvent *e) {
        fn(*static_cast<const T*>(e));
    }
};


// a container holding callback functions
std::unordered_map<size_t/*event*/, std::unique_ptr<BaseWrapper>/*callback*/> _functions;


// register callback funtion associated with specific event
template<typename EVT>  
void registerCallback(std::function<void(const EVT &)> cb)
{
    std::cout << "store callback associated with event " << typeid(EVT).name() << " [" << typeid(EVT).hash_code() << "]" << std::endl;
    auto w = std::make_unique<Wrapper<EVT>>();
    w->fn = cb;
    _functions[ typeid(EVT).hash_code() ] = std::move(w);
}


// trigger callback function
void triggerCallback(const BaseEvent* e)
{
    std::cout << "trigger callback with event " << typeid(*e).name() << " [" << typeid(*e).hash_code() << "]" << std::endl;
    (*_functions[ typeid(*e).hash_code() ] )(e);
}

// callback function for DerivedEvent_1
void callback_1(const DerivedEvent_1 &event_1)
{
    std::cout << "callback_1 called" << std::endl;
}

// callback function for DerivedEvent_2
void callback_2(const DerivedEvent_2 &event_2)
{
    std::cout << "callback_2 called" << std::endl;
}

int main(int argc, char *argv[])
{
    registerCallback<DerivedEvent_1>( [](DerivedEvent_1 e) { callback_1(e); } );
    registerCallback<DerivedEvent_2>( [](DerivedEvent_2 e) { callback_2(e); } );

    DerivedEvent_1 e1;
    DerivedEvent_2 e2;

    triggerCallback(&e1);
    triggerCallback(&e2);

    return 1;
}

可以在性能方面改进包装器（例如，使用静态成员方法而不是多态，留给读者作为练习）。
解决方案背后的基本思想是所谓的type-erasure Google会帮助您查找有关该内容的更多详细信息。

std :: function的容器，具有多态类型作为函数参数

1 个答案: