Question

我知道有很多与此主题相关的问题，但似乎对我没什么用。

我有一项服务，它接收来自多个活动的广播，并且我使用不同的行动来区分它们，以便接收每个广播。

这是我的代码

MyService.java //这是服务类

private BroadcastReceiver SleepTimeReceiver = new BroadcastReceiver() {
    @Override
    public void onReceive(Context context, Intent intent) {
        Log.d(TAG,"SleepTimeReceiver onReceive is called");
        if (intent.getAction().equals("sleepTimeFinished")) {
            Log.d(TAG,"intents are matching");
        }
    }
};

@Override
public void onCreate() {
    Log.d(TAG,"onCreate is called");
    .
    .
    registerReceiver(SleepTimeReceiver,new IntentFilter("sleepTimeFinished"));
}

@Override
public void onDestroy() {
    Log.d(TAG, "on destroy is called");
    unregisterReceiver(SleepTimeReceiver);
}

MyActivity.java //这是活动类

@Override
protected void onCreate(Bundle savedInstanceState) {
    Log.d(TAG,"About to send broadcast");
    Intent sleepTimeFinishedIntent = new Intent(this, MyService.class);
    sleepTimeFinishedIntent.setAction("sleepTimeFinished");
    sendBroadcast(sleepTimeFinishedIntent);
    Log.d(TAG,"broadcast has been sent");
}

我还尝试在清单文件中添加接收器，但无济于事。在logcat中，我可以看到除接收器的onReceive方法之外的所有方法的日志。有人可以帮我这个。这个简单的问题一直困扰着我几个小时。

Answer 1

你开始服务了吗？我没有看到在onCreate开始，你在那里发送广播 - 也许收件人还没有注册？

Answer 2

在我看来，您应该使用LocalBroadcastManager，因为您只处理从您自己的应用程序中发送的广播。

因此，onCreate() MyService.java BroadcastReceiver注册您的LocalBroadcastManager.getInstance(this).registerReceiver(sleepTimeReceiver, new IntentFilter("sleepTimeFinished"));，如下所示：

onCreate()

然后从MyActivity.java Intent sleepTimeFinishedIntent = new Intent("sleepTimeFinished"); LocalBroadcastManager.getInstance(this).sendBroadcast(sleepTimeFinishedIntent);发送您的广播：

onDestroy()

在MyService.java的LocalBroadcastManager.getInstance(this).unregisterReceiver(sleepTimeReceiver);中取消注册本地广播接收器，如下所示：

sleepTimeReceiver

您可能已经注意到我还将广播接收器的名称改为以小写字母开头，只是为了保持一致性。所以它是SleepTimeReceiver而不是asdf = (['0', ...], ['1', ...], ['2', ...], ['3.0', ...], ['3.1', ...], ['3.2', ...], ['4', ...] , ['5.0', ...], ['5.1', ...])。

服务中的广播接收器未接收意图

2 个答案: