如何将终端命令添加到我的Python脚本中? 我有一个包含更多图像/视频的图像/视频/文件夹的大文件夹,我想将它们组织在一个HTML文件中(FirstPage.html)。
该脚本首先列出目录中的所有文件:
def listFiles():
command = "ls"
output = Popen(command, stdout=PIPE) #This is the only way i found to run LS in terminal and get the output
x = str(output.stdout.read())
x = x[2:-3]
x += (" ")
x = re.sub(r"\\n", " ", x)
y = ""
finalLIST = list()
for o in x:
if o == " ":
finalLIST.append(str(y))
y = ""
else:
y += o
return finalLIST #returns a list with all files in the current directory
然后检查文件是图像还是视频,如果是视频,则会添加到HTML文件中:
<video controls>
<source src="videoName.mp4" type="video/WebM/mp4">
<source src="videoName.ogg" type="video/ogg">
Video not suported!
</video>
如果是它添加的图像:
<img src="ImageName.jpg" alt="image"/>
代码是:
def organize():
DIRECTORIES = listFiles()
IMAGE = [".png", ".jpg"]
VIDEO = [".webm", ".mp4"]
for x in DIRECTORIES:
if not re.search(".", x):
#This means that it is a directory
#I want to CD into this directory and run listFiles() and then organize() it. How i do it?
else:
for y in IMAGE:
ADDimg = "\n<img src=\"" + x + "\" alt=\"imagem\"/>\n"
if re.search(y, x):
with open(FirstPage.html) as f:
for line in f:
if line = "<!--IMAGES-->":
f.write(ADDimg)
break
f.write(ADDimg)
for y in VIDEO:
ADDvideo = """\n<video controls>
<source src=\"""" + x
"""\" type="video/WebM/mp4">
<source src="video.ogg" type="video/ogg/WebM">
Video not suported!
</video>\n
"""
if re.search(y, x):
with open(FirstPage.html) as f:
for line in f:
if line = "<!--VIDEOS-->":
f.write(ADDvideo)
break
这是FirstPag.html:
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>The first page</title>
</head>
<body>
<!--IMAGES-->
<!--VIDEOS-->
</body>
</html>
我希望这个脚本列出目录中的文件,将那里的所有图像/视频添加到HTML文件中,然后cd进入那里的文件夹,并以递归方式执行相同的操作。任何sugestions?
谢谢!
答案 0 :(得分:1)
不要对语言库中存在的内容执行cd
/ ls
命令:os.listdir()
。
你可以像这样使用它:
from os import listdir
from os.path import isfile, join
files = [f for f in listdir(mypath) if isfile(join(mypath, f))]
同样,您可以使用isdir
来检查目录。
您可以组合上述命令来进行递归目录遍历。