bash选择文件，运行grep，并在新创建的目录中重命名

Question

我正在尝试// Protected route test module.exports.memberInfo = function(req, res){ //how do i access the "app" here? res.status(200).send({ user: req.user }); } 目录中的文件，在其上运行select，然后将其重命名为已创建的新目录。除了将重命名应用于新目录中的文件之外，下面的grep执行以上所有操作。因此，如果选择了bash，则在运行file1.txt之后，该文件将在新目录中重命名为bash。它似乎很有效但尚未完成。谢谢你:)。

文件目录

file1_OTHER.txt

击

file1.txt
file2.txt

新目录 - # select file printf "please select a file to analyze with entered gene or genes \n" select file in $(cd /home/files;ls); do break done echo $file "will be used" # enter gene input printf "%s \n" "Please enter id, use a comma between multiple:" OLDIFS=$IFS IFS="," read -a id for (( i = 0; i < ${#id[@]}; i++ )) do printf "%s\n" "${id[$i]}" >> /home/list.bed done # match input with id grep -wFf /home/list.bed /home/targets.bed > /home/match.bed logfile=/home/process.log for file in /home/$file; do echo "Start selected file creation: Date: $(date) - File: $file" bname=$(basename $file) pref=${bname%%.txt} cp -f "$file" /home/reads/"${pref%%_OTHER}.txt" echo "End selected file creation: $(date) - File: $file" done >> "$logfile" （执行/home/reads后所需的输出）

bash

Answer 1

以下对我有用，我只需要设置IFS，因此它不会寻找,作为文件分隔符。谢谢你:)。

# enter gene input
printf "%s \n" "Please enter id, use a comma between multiple:"
OLDIFS=$IFS
IFS=$OLDIFS
read -a id
for (( i = 0; i < ${#id[@]}; i++ ))
do
printf "%s\n" "${id[$i]}" >> /home/list.bed
done

# select file
printf "please select a file to analyze with entered gene or genes  \n"
select file in $(cd /home/files;ls); do 
break
done
echo $file "will be used"

# match input with id
grep -wFf /home/list.bed /home/targets.bed > /home/match.bed
logfile=/home/process.log
for file in /home/$file; do
echo "Start selected file creation: Date: $(date) - File: $file"
bname=$(basename $file)
pref=${bname%%.txt}
cp -f "$file" /home/reads/"${pref%%_OTHER}.txt"
echo "End selected file creation: $(date) - File: $file"
done >> "$logfile"