Laravel - 如何在orWhere方法中更改表格?

时间:2016-06-18 15:13:17

标签: php mysql laravel

我想做这样的事情:

$posts= Status::where('users_id',$user->id)->orWhere(DB::table('user_status_share.user_id', $user->id))->orderBy('created_at', 'DESC')->get();

但是我收到一个错误: strtolower()希望参数1为字符串,给定对象 - 如何在“orWhere”方法中更改表格?这可能吗?如果不是 - 如何在一个查询中使用2个表?

架构(状态):

public function up()
{
    Schema::create('users_status', function (Blueprint $table) {
        $table->increments('id')->unique();
        $table->longText('status_text');
        $table->integer('users_id')->unsigned();
        $table->timestamps();
    });
}

/**
 * Reverse the migrations.
 *
 * @return void
 */
public function down()
{
    Schema::drop('users_status');
}

架构(StatusShare):

public function up()
{
    Schema::create('user_status_share', function (Blueprint $table) {
        $table->increments('id');
        $table->integer('status_id');
        $table->integer('user_id');
        $table->timestamps();
    });
}

/**
 * Reverse the migrations.
 *
 * @return void
 */
public function down()
{
    Schema::drop('user_status_share');
}

型号状态:

namespace App\Eloquent;

use Illuminate\Database\Eloquent\Model;

class Status extends Model
{
    public $timestamps = true;
    protected $table = 'users_status';
    protected $guarded = ['id'];

    public function comments()
    {
        return $this->hasMany(StatusComments::class);
    }

    public function likes()
    {
        return $this->hasMany(StatusLikes::class);
    }

    public function shares()
    {
        return $this->hasMany(StatusShare::class);
    }

}

型号状态分享:

<?php

namespace App\Eloquent;

use Illuminate\Database\Eloquent\Model;

class StatusShare extends Model
{
    public $timestamps = true;
    protected $table = 'user_status_share';
    protected $guarded = ['id'];

    public function status()
    {
        return $this->hasOne(Status::class);
    }
}

1 个答案:

答案 0 :(得分:0)

我认为你应该尝试这样的事情

调整它,我没有测试它

 $posts = DB::table('status')->where('users_id',$user->id)->orWhere(function ($query) use ($user) {
                $query->table('user_status_share')->where('user_id', $user->id);
            })
            ->get();

你可以分享更多信息,因为我觉得可以通过关系以简单的方式达到这些信息(在我们的模型中显示数据库结构和关系)