Question

我已经尝试了很多次，但是我无法对远程API执行简单的POST请求。我需要发布用户名和密码才能获得登录授权。以下是代码：

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我做了另一个版本，使用NSDictionary和Json解析（API使用json）

NSURL * url = [NSURL URLWithString:@"http://thapi.xyz/auth/login"];
NSString *postData = @"username=emailExample@gmail.com&password=123456";
NSData * dataBody = [postData dataUsingEncoding:NSUTF8StringEncoding allowLossyConversion:YES];
NSString *postLenght = [NSString stringWithFormat:@"%d",[dataBody length]];

NSMutableURLRequest * request = [NSMutableURLRequest requestWithURL:url cachePolicy:NSURLRequestReloadIgnoringCacheData timeoutInterval:10];
[request setHTTPMethod:@"POST"]; 
[request setValue:@"application/x-www-form-unlencoded" forHTTPHeaderField:@"Content-Type"];
[request setValue:postLenght forHTTPHeaderField:@"Content-Lenght"];
[request setHTTPBody:dataBody];

[NSURLConnection sendAsynchronousRequest:request queue:[[NSOperationQueue alloc]init] completionHandler:^(NSURLResponse * _Nullable response, NSData * _Nullable data, NSError * _Nullable connectionError) {
    NSLog(@" ERROR %@, RESPONSE %@ AND DATA %@",connectionError,response,[[NSString alloc] initWithData:data encoding:NSASCIIStringEncoding]);
}];

这是两个代码的结果：

NSDictionary * login = @{@"username":@"exampleMail@gmail",@"password":@"123456"};
NSData * jsonData = [NSJSONSerialization dataWithJSONObject:login options:NSJSONWritingPrettyPrinted error:nil];
NSString *postLenght = [NSString stringWithFormat:@"%d",[jsonData length]];

NSMutableURLRequest * request = [NSMutableURLRequest requestWithURL:url cachePolicy:NSURLRequestReloadIgnoringCacheData timeoutInterval:10];
[request setHTTPMethod:@"POST"]; 
[request setValue:@"application/x-www-form-unlencoded" forHTTPHeaderField:@"Content-Type"];
[request setValue:postLenght forHTTPHeaderField:@"Content-Lenght"];
[request setHTTPBody:jsonData];

[NSURLConnection sendAsynchronousRequest:request queue:[[NSOperationQueue alloc]init] completionHandler:^(NSURLResponse * _Nullable response, NSData * _Nullable data, NSError * _Nullable connectionError) {
  NSLog(@" ERROR %@, RESPONSE %@ AND DATA %@",connectionError,response,[[NSString alloc] initWithData:data encoding:NSASCIIStringEncoding]);
}];

我非常感谢所有的答案，对不起我糟糕的英语......

Answer 1

可能是标题变量的拼写错误（“Content-Lenght”拼写错误）：

[request setValue:postLenght forHTTPHeaderField:@"Content-Length"];

Answer 2

不推荐使用NSURLConnection。请使用nsurlsession尝试此代码....

//replace the following code with your request params
    NSUserDefaults *prefs = [NSUserDefaults standardUserDefaults];
        NSString *clientSessionId = [prefs stringForKey:@"clientSession"];

        NSString *bodyString = [NSString stringWithFormat:@"[\"%@\",{\"session_token\":\"%@\",\"request\":[\"GetUnitDetails\",{}]}]",clientSessionId,clientSessionId];
        //Make mutable url request        
        NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:[Settings getMobileUrl]]];
        NSData *postData = [bodyString dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
        [request setHTTPBody:postData];
    //Change the http method as per your own choice
        [request setHTTPMethod:@"POST"];
        NSString *postLength = [NSString stringWithFormat:@"%lu", (unsigned long)[postData length]];
        [request setValue:postLength forHTTPHeaderField:@"Content-Length"];


        [[[NSURLSession sharedSession] dataTaskWithRequest:request completionHandler:^(NSData *data,NSURLResponse *response,NSError *connectionError)
          {
              if ([data length] > 0 && connectionError == nil)

              {
         NSError *localError = nil;
        self.parsedObject = [NSJSONSerialization JSONObjectWithData:data options:0 error:&localError];
        NSString* unitResponse = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];

        NSData *jsonData = [unitResponse dataUsingEncoding:NSUTF8StringEncoding];
        NSMutableArray *jsonDic = [NSJSONSerialization JSONObjectWithData:jsonData options:NSJSONReadingAllowFragments error:nil];   




                  }else {
    NSLog(@"No response received");
}

          }]resume];

Answer 3

您可以尝试使用NSDictionary作为参数。以下内容将正确地将参数发送到JSON服务器。

NSError *error;

NSURLSessionConfiguration *configuration = [NSURLSessionConfiguration defaultSessionConfiguration];
NSURLSession *session = [NSURLSession sessionWithConfiguration:configuration delegate:self delegateQueue:nil];
NSURL *url = [NSURL URLWithString:@"http://thapi.xyz/auth/login"];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url
                                                       cachePolicy:NSURLRequestUseProtocolCachePolicy
                                                   timeoutInterval:60.0];

[request addValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
[request addValue:@"application/json" forHTTPHeaderField:@"Accept"];

[request setHTTPMethod:@"POST"];
NSDictionary *login = [[NSDictionary alloc] initWithObjectsAndKeys: @"username":@"exampleMail@gmail",@"password":@"123456",
                     nil];
NSData *postData = [NSJSONSerialization dataWithJSONObject:login options:0 error:&error];
[request setHTTPBody:postData];


NSURLSessionDataTask *postDataTask = [session dataTaskWithRequest:request completionHandler:^(NSData *data, NSURLResponse *response, NSError *error) {

}];

[postDataTask resume];

希望这项工作正常......：）

Answer 4

还要尝试纠正“setValue：postLenght”，因为我猜这不存在，并且可能会将Content-Length设置为0。

POST方法导致状态码400 ios

4 个答案: