Question

我不明白，我的代码有什么问题？我创建了2个表''users'和'messages'，但是当我尝试将数据插入到messages表中时，引发了这个奇怪的错误 -

sqlite3.OperationalError: table messages has no column named message

这是我的代码

conn = sqlite3.connect(self.path)
cur = conn.cursor()
# Create the table 'users'
cur.execute('''create table if not exists users
            (uid INTEGER NOT NULL PRIMARY KEY AUTOINCREMENT UNIQUE,
             name TEXT NOT NULL)''')
conn.commit()
# Create the table 'messages'
cur.execute('''create table if not exists messages (uid INTEGER NOT NULL, message TEXT)''')
conn.commit()
example_data1 = [(1,'Alex'), (2,'Jane'), (3,'Max'), (4,'Lui')]
example_data2 = [(1,'Hi!!!'), (1, 'Hello...'), (1, 'See you late!:)))'),
                 (2, 'Nice to meet you John'), (2, 'Bye-bye...'),
                 (3, 'Good morning')]
# Inserts example data to table -'users'
cur.executemany('''INSERT OR IGNORE INTO users(uid, name) VALUES(?,?)''', example_data1)
conn.commit()
cur.executemany('''INSERT INTO messages(uid, message) VALUES(?,?)''', example_data2)
conn.commit()
# Takes users name and count of messages of this users
cur.execute('SELECT users.name, count(messages.message) as count_msg FROM users LEFT JOIN messages ON users.uid = messages.uid GROUP BY users.name ORDER BY count_msg DESC')
result = cur.fetchall()
cur.close()

Answer 1

您正在使用create table if not exists，这将保留该表的任何旧版本。

要确保表具有所需的架构，请使用普通create table。可以使用drop table if exists删除任何旧表。

SQLite3 + Python sqlite3.OperationalError：表A没有名为message B

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