Question

我正在开发一个Android应用程序，我必须实现一个解析我的JSON并返回给我某些结果的函数。

例如，我有一个带有此strcutures的JSON：

[  
   {  
      "date":"17-06-2016",
      "desc":"My description",
      "id":"9",
      "img":"http:\/\/myurl\/pathimage\/image.jpg",
      "text":"Lorem Ipsum.",
      "title":"My title"
   },   {  
      "date":"14-06-2015",
      "desc":"My description 2",
      "id":"5",
      "img":"http:\/\/myurl\/pathimage\/image.jpg",
      "text":"Lorem Ipsum 2.",
      "title":"My title 2"
   }

]

我只需要选择id = 9的对象，我该怎么做？我如何以编程方式选择JSON对象区分尊重id？

我知道如何解析JSON，但我不知道如何以编程方式选择区分ID的JSON对象。

******编辑1 ******

JSONArray newsReq;
        try {
            newsReq = new JSONArray(result.toString());
            for (int i = 0; i < newsReq.length(); i++) {
                try {
                  if(obj.getInt("id")=='9'){
                    JSONObject obj = newsReq.getJSONObject(i);
                    obj.getString("img");
                    obj.getInt("id");
                    obj.getString("title");
                 }
                } catch (JSONException e) {
                    Log.wtf("BulgariLog: ", e);
                }
            }
        } catch (JSONException e) {
            Log.wtf("BulgariLog: ", e);
        }

Answer 1

假设您正在像这样粘贴JSON数组，

JSONArray jsonArray = new JSONArray(response);

        for (int i = 0; i < jsonArray.size(); i++) {

            JSONObject jsonObject = jsonArray.getJSONObject(i);

            // get the id of current JSON object
            String id = jsonObject.getString("id");

            // check if the id matches with your required id
            if (id.contains("9")) {
                // the JSON object matches with your desired one
                // get the remaining values here
            } else {
            // skip the object since it doesn't matches your given id 
            }
        }

如何从JSON中选择某个数据

1 个答案: