Question

我试图通过Selenium抓住这个site。

我想点击＆＃34;下一页＆＃34; buttom，为此我做了：

 driver.find_element_by_class_name('pagination-r').click()

它适用于许多页面，但并非适用于所有页面，我收到此错误

WebDriverException: Message: Element is not clickable at point (918, 13). Other element would receive the click: <div class="linkAuchan"></div>

始终为this page

我看了this question

我试过这个

driver.implicitly_wait(10)
el = driver.find_element_by_class_name('pagination-r')
action = webdriver.common.action_chains.ActionChains(driver)
action.move_to_element_with_offset(el, 918, 13)
action.click()
action.perform()

但是我得到了同样的错误

Answer 1

另一个元素是覆盖要单击的元素。您可以使用execute_script()点击此内容。

element = driver.find_element_by_class_name('pagination-r')
driver.execute_script("arguments[0].click();", element)

Answer 2

我有一个类似的问题，使用ActionChains没有解决我的错误： WebDriverException：消息：未知错误：元素在点（5处）不可单击 74,892）

如果您不想使用execute_script，我找到了一个很好的解决方案：

    from selenium.webdriver.common.keys import Keys #need to send keystrokes

    inputElement = self.driver.find_element_by_name('checkout')

    inputElement.send_keys("\n") #send enter for links, buttons

或

    inputElement.send_keys(Keys.SPACE) #for checkbox etc

Answer 3

由于元素在浏览器中不可见，首先需要向下滚动到元素这可以通过执行 javascript 来执行。

element = driver.find_element_by_class_name('pagination-r')
driver.execute_script("arguments[0].scrollIntoView();", element)
driver.execute_script("arguments[0].click();", element)

Answer 4

我已经编写了处理此类异常的逻辑。

   def find_element_click(self, by, expression, search_window=None, timeout=32, ignore_exception=None,
                       poll_frequency=4):
    """It find the element and click then  handle all type of exception during click

    :param poll_frequency:
    :param by:
    :param expression:
    :param timeout:
    :param ignore_exception:list It is a list of exception which is need to ignore.
    :return:
    """
    if ignore_exception is None:
        ignore_exception = []

    ignore_exception.append(NoSuchElementException)
    if search_window is None:
        search_window = self.driver

    end_time = time.time() + timeout
    while True:
        try:
            web_element = search_window.find_element(by=by, value=expression)
            web_element.click()
            return True
        except tuple(ignore_exception) as e:
            self.logger.debug(str(e))
            if time.time() > end_time:
                self.logger.exception(e)
                time.sleep(poll_frequency)
                break
        except Exception as e:
            raise
    return False

Answer 5

使用显式等待而不是隐式。

 new WebDriverWait(TestingSession.Browser.WebDriver, TimeSpan.FromSeconds(10)).Until(ExpectedConditions.ElementExists((By.ClassName("pagination-r'"))));

Answer 6

即使在元素上使用wait之后，如果仍然收到element not clickable错误，请尝试以下解决方法之一：

使用Action移至element的位置，然后在perform上运行action

WebElement element = driver.findElement(By("element_path"));
Actions actions = new Actions(driver);
actions.moveToElement(element).click().perform();`

检查element和wait上的覆盖层或微调器是否不可见

By spinnerimg = By.id("spinner ID");
WebDriverWait wait = new WebDriverWait(driver, timeOutInSeconds);
wait.until(ExpectedConditions.invisibilityOfElementLocated(spinnerimg ));

希望这会有所帮助

Selenium-Debugging：元素在点（X，Y）处不可点击

6 个答案: