Question

我的字符串是这样的：

2 cups - Desiccated Coconut, 2.5 cups - Maida, 1.25 cup - Butter, 1/2 tsp - Baking soda, 1.25 cup - Powdered Sugar, 1/2 tsp - Baking powder, 2-3 drops - Vanilla essence

我希望输出格式如下：

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Answer 1

这是一个解决方案，您只需要最终为变量指定正确的名称。下次，请证明你尝试了一些东西或调查了一下。您将需要包txt= c("2 cups - Desiccated Coconut, 2.5 cups - Maida, 1.25 cup - Butter, 1/2 tsp - Baking soda, 1.25 cup - Powdered Sugar, 1/2 tsp - Baking powder, 2-3 drops - Vanilla essence") splits_per_ingredients = strsplit(txt,c(","))[[1]] split_per_quantity = sapply(splits_per_ingredients,strsplit," - ") split_per_dose=t(sapply(split_per_quantity,FUN=function(vec) {c(strsplit(stringr::str_trim(vec[1])," ")[[1]],vec[2])}))来删除尾随和前导空格。

                              [,1]   [,2]    [,3]                
 2 cups - Desiccated Coconut  "2"    "cups"  "Desiccated Coconut"
  2.5 cups - Maida            "2.5"  "cups"  "Maida"             
  1.25 cup - Butter           "1.25" "cup"   "Butter"            
  1/2 tsp - Baking soda       "1/2"  "tsp"   "Baking soda"       
  1.25 cup - Powdered Sugar   "1.25" "cup"   "Powdered Sugar"    
  1/2 tsp - Baking powder     "1/2"  "tsp"   "Baking powder"     
  2-3 drops - Vanilla essence "2-3"  "drops" "Vanilla essence"

输出：

<script type="text/javascript">
    var arr = [];
    var names = [{name : 'George'}, {name : 'Ringo'}, {name : 'Paul'}, {name : 'John'}];
    var surnames = [{surname : 'Harrison'}, {surname : 'Starr'}, {surname : 'McCartney'}, {surname : 'Lennon'}];

    for (i = 0; i < names.length; i++) {
            arr['firstname'] = names[i];
        for (j = 0; j < surnames.length; j++) {
            arr['firstname']['surname'] = surnames[j];
            arr['firstname']['surname']['index'] = i;
            console.log(arr);
        }
    }
</script>

Answer 2

> library(dplyr)
> library(tidyr)
> library(stringr)
> 
> str = '2 cups - Desiccated Coconut, 2.5 cups - Maida, 1.25 cup - Butter, 1/2 tsp - Baking soda, 1.25 cup - Powdered Sugar, 1/2 tsp - Baking powder, 2-3 drops - Vanilla essence'
> 
> df = data.frame(Qty = unlist(strsplit(str, ',')))
> df
                           Qty
1  2 cups - Desiccated Coconut
2             2.5 cups - Maida
3            1.25 cup - Butter
4        1/2 tsp - Baking soda
5    1.25 cup - Powdered Sugar
6      1/2 tsp - Baking powder
7  2-3 drops - Vanilla essence
> 
> df = df %>% separate(Qty, c('Unit', 'Ingredient'), ' - ')
> df
        Unit         Ingredient
1     2 cups Desiccated Coconut
2   2.5 cups              Maida
3   1.25 cup             Butter
4    1/2 tsp        Baking soda
5   1.25 cup     Powdered Sugar
6    1/2 tsp      Baking powder
7  2-3 drops    Vanilla essence
> 
> # remove start & end white spaces (stringr library)
> # or else you can't separate correctly
> df$Unit = str_trim(df$Unit)
> df = df %>% separate(Unit, c('Qty', 'Unit'), ' ')
> df
   Qty  Unit         Ingredient
1    2  cups Desiccated Coconut
2  2.5  cups              Maida
3 1.25   cup             Butter
4  1/2   tsp        Baking soda
5 1.25   cup     Powdered Sugar
6  1/2   tsp      Baking powder
7  2-3 drops    Vanilla essence

如何在R中将 - 和，分隔的字符串转换为表格格式？

2 个答案: