Question

使用简单的控制器尝试使用Play framework 2.5时出现的错误消息令人困惑。这就是我正在做的事情：

object UserController extends Controller {

  def login = Action.async(BodyParsers.parse.json) { request =>
    val body = request.body.validate[UserLogin]
    // call the userService and validate the credentials
    body.fold(
      errors => {
        BadRequest(Json.obj("status" -> "error", "message" -> JsError.toFlatJson(errors)))
      }, // error here
      message => {
        Ok("")
      } // error here
    )
  }
}

我收到错误消息：

"Expression of type Result does not conform to expected type _X"

Answer 1

我需要将电话包裹在未来！所以这是如何做到的！

object UserController extends Controller {

  def login = Action.async(BodyParsers.parse.json) { request =>
    val body = request.body.validate[UserLogin]
    // call the userService and validate the credentials
    body.fold(
      errors => {
        Future.successful { BadRequest(Json.obj("status" -> "error", "message" -> JsError.toFlatJson(errors))) }
      }, // error here
      message => {
        Future.successful { Ok("") }
      } // error here
    )
  }
}

使用简单控制器播放框架2.5错误

1 个答案: