Question

SELECT DISTINCT IWTUSER_ALARMS.NAME, IWTUSER_ALARMS.AID, IWTUSER_ALARMS.DUR, 
   Int(CInt([DUR])/86400) AS DAYS, Int((CInt([DUR]) Mod 86400)/3600) AS HOURS, 
   Int(((CInt([DUR]) Mod 86400) Mod 3600)/360) AS MINUTES, 
   Int((((CInt([DUR]) Mod 86400) Mod 3600) Mod 360)/60) AS SECONDS
FROM IWTUSER_ALARMS
   WHERE (((CDate(Format([IWTUSER_ALARMS].[ITIME],"0000-00-00 00\:00\:00 ")))>=Date()-10))
GROUP BY IWTUSER_ALARMS.NAME, IWTUSER_ALARMS.AID, IWTUSER_ALARMS.DUR, 
   CInt([DUR])/86400, CInt([DUR]) Mod 86400, (CInt([DUR]) Mod 86400) Mod 3600, 
   ((CInt([DUR]) Mod 86400) Mod 3600) Mod 360
ORDER BY IWTUSER_ALARMS.DUR DESC;

Answer 1

经过这么多试验和错误以及从不同来源收集了一些信息后，我能够解决这个问题 - 以下是工作代码。

SELECT T.ID, T.NAME, ACOUNT AS AlarmCOUNT

FROM（

SELECT DISTINCT（IWTUSER_ALARMS.NAME）AS NAME，COUNT（IWTUSER_ALARMS.NAME）AS ACOUNT，IWTUSER_ALARMS.AID AS ID

FROM IWTUSER_ALARMS

WHERE (((CDate(Format([IWTUSER_ALARMS].[ITIME],"0000-00-00 00\:00\:00 ")))>=Date()-1))

GROUP BY IWTUSER_ALARMS.NAME，IWTUSER_ALARMS.AID

）AS T. ORDER BY T.NAME DESC;

我收到一条错误说＆＃34;溢出＆＃34;在我尝试使用CDate时在MS Access查询中

1 个答案: