Question

我在wordpress上有一个表单，我试图在插件上创建，我试图发布它，但是当我提交表单页面重新加载。

if (isset( $_POST['plugin-guide-info-form-submitted'] ) ) {
            $hidden_field = esc_html ( $_POST['plugin-guide-info-form-submitted'] ) ;

            if( $hidden_field == 'Y' ) {

                $guide_name = esc_html( $_POST['wpt_guide_name'] );

                $guide_description = esc_html( $_POST['wpt_guide_description'] );

                echo $guide_name;
                echo $guide_description;

            }
        }
    }

我的表格是

$html .= '<form name = "plugin-guide-info" method="post" action="" enctype="multipart/form-data">' . "\n";
ob_start();
                settings_fields( $this->parent->_token . '_settings' );
                do_settings_sections( $this->parent->_token . '_settings' );
                $html .= ob_get_clean();

                $html .= '<input type ="hidden" name="plugin-guide-info-form-submitted" value="Y" />' . "\n";

                $html .= '<p class="submit">' . "\n";
                    $html .= '<input name="plugin-guide-info-Submit" type="submit" class="button-primary" value="' . esc_attr( __( 'Save' , 'assist' ) ) . '" />' . "\n";
                $html .= '</p>' . "\n";
            $html .= '</form>' . "\n";

设置

private function settings_fields () {

        $settings['standard'] = array(
            'title'                 => __( '', 'assist' ),
            'description'           => __( '', 'assist' ),
            'fields'                => array(
                array(
                    'id'            => 'guide_name',
                    'name'          => 'guide_name',
                    'label'         => __( 'Guide Name' , 'assist' ),
                    'description'   => __( '', 'assist' ),
                    'type'          => 'text',
                    'default'       => '',
                    'placeholder'   => __( 'Guide Name', 'assist' )
                ),
                array(
                    'id'            => 'guide_description',
                    'name'          => 'guide_description',
                    'label'         => __( 'Guide Description' , 'assist' ),
                    'description'   => __( '', 'assist' ),
                    'type'          => 'textarea',
                    'default'       => '',
                    'placeholder'   => __( 'Plug in Description and links to tutoials', 'assist' )
                )
            )
        );

        $settings = apply_filters( $this->parent->_token . '_settings_fields', $settings );

        return $settings;
    }

我知道指南说明和指南名称的名称与settings_fields函数和html不同，因为当我在开发人员工具上查看它时，它已将wpt_添加到name-value。

我开始在github上使用wordpress插件模板

所以我的问题是，为什么我无法让它发布并返回？

无法退回表格上的帖子

0 个答案: