所以我很难找到答案但没有成功。
我想在我的GET方法中收到一个“复杂”的参数作为JSON。
我怎么能这样做?
这是方法:
@RequestMapping(method = RequestMethod.GET, value = "/test2", consumes = {MediaType.APPLICATION_JSON_VALUE})
@ResponseBody
public ResponseEntity<?> test2(@RequestParam PojoParam pojoParam) {
return new ResponseEntity<>(pojoParam, HttpStatus.OK);
}
这是PojoParam:
public class PojoParam implements java.io.Serializable {
private String stringVariable;
private int intVariable;
public PojoParam() {
}
public String getStringVariable() {
return stringVariable;
}
public int getIntVariable() {
return intVariable;
}
public void setStringVariable(String stringVariable) {
this.stringVariable = stringVariable;
}
public void setIntVariable(int intVariable) {
this.intVariable = intVariable;
}
}
调用示例:
... /test2?pojoParam={intVariable:2, stringVariable:"as"}
回应示例:
{
"timestamp": "2016-06-16T15:09:36Z",
"status": 500,
"error": "Internal Server Error",
"exception": "org.springframework.beans.ConversionNotSupportedException",
"message": "Failed to convert value of type 'java.lang.String' to required type 'com.htravel.tng.pe.resources.PojoParam'; nested exception is java.lang.IllegalStateException: Cannot convert value of type [java.lang.String] to required type [com.htravel.tng.pe.resources.PojoParam]: no matching editors or conversion strategy found",
"path": "/rest/availability/test2"
}
我也试过@RequestPart而没有成功。
有什么建议吗?
谢谢。