Question

使用下面的代码，我只能启动Visual Studio 2008命令提示符，但现在我必须将网站发布到本地驱动器上的目标路径。

我需要c＃代码，它执行类似以下命令：

msbuild / target：Build / p：BuildingProject = true; OutDir = C：\ Temp \ build \ ccosapp.sln我的第一次尝试（失败 - 什么也没做）：

以下是我尝试的代码，它没有做任何事情：

ProcessStartInfo oInfo = new ProcessStartInfo(@"C:\Program Files (x86)\Microsoft Visual Studio 9.0\VC\vcvarsall.bat", @"msbuild C:\Users\Johan\Documents\Visual Studio 2008\Projects\PRJAPP\PRJAPP.sln");
oInfo.UseShellExecute = false;
oInfo.ErrorDialog = false;
oInfo.CreateNoWindow = true;
oInfo.RedirectStandardOutput = true;

System.Diagnostics.Process p = System.Diagnostics.Process.Start(oInfo);
System.IO.StreamReader oReader2 = p.StandardOutput;
string sRes = oReader2.ReadToEnd();
oReader2.Close();

另一次尝试（也失败）：

string strCmdText = "/k \"C:\\Program Files (x86)\\Microsoft Visual Studio 9.0\\VC\\vcvarsall.bat\" && msbuild /p:OutDir=C:\\Temp\\build \"C:\\Users\\Johan\\Documents\\Visual Studio 2008\\Projects\\CCOSApp\\ccosapp.sln\"";
System.Diagnostics.Process.Start("CMD.exe", strCmdText);

我在CMD窗口中收到错误：

'C：\ Program'未被识别为内部或外部命令，可操作程序或批处理文件。

最后一次尝试（也失败了 - 得到与第二次尝试相同的错误）：

/// <span class="code-SummaryComment"><summary></span>
/// Executes a shell command synchronously.
/// <span class="code-SummaryComment"></summary></span>
/// <span class="code-SummaryComment"><param name="command">string command</param></span>
/// <span class="code-SummaryComment"><returns>string, as output of the command.</returns></span>
public void ExecuteCommandSync(object command)
{
    try
    {
        // create the ProcessStartInfo using "cmd" as the program to be run,
        // and "/c " as the parameters.
        // Incidentally, /c tells cmd that we want it to execute the command that follows,
        // and then exit.
        System.Diagnostics.ProcessStartInfo procStartInfo =
            new System.Diagnostics.ProcessStartInfo("cmd", "/k " + command);

        // The following commands are needed to redirect the standard output.
        // This means that it will be redirected to the Process.StandardOutput StreamReader.
        procStartInfo.RedirectStandardOutput = true;
        procStartInfo.UseShellExecute = false;
        // Do not create the black window.
        procStartInfo.CreateNoWindow = false;
        // Now we create a process, assign its ProcessStartInfo and start it
        System.Diagnostics.Process proc = new System.Diagnostics.Process();
        proc.StartInfo = procStartInfo;
        proc.Start();
        // Get the output into a string
        string result = proc.StandardOutput.ReadToEnd();
        // Display the command output.
        Console.WriteLine(result);
    }
    catch (Exception objException)
    {
        // Log the exception
    }
}

/// <span class="code-SummaryComment"><summary></span>
/// Execute the command Asynchronously.
/// <span class="code-SummaryComment"></summary></span>
/// <span class="code-SummaryComment"><param name="command">string command.</param></span>
public void ExecuteCommandAsync(string command)
{
    try
    {
        //Asynchronously start the Thread to process the Execute command request.
        System.Threading.Thread objThread = new System.Threading.Thread(new ParameterizedThreadStart(ExecuteCommandSync));
        //Make the thread as background thread.
        objThread.IsBackground = true;
        //Set the Priority of the thread.
        objThread.Priority = ThreadPriority.AboveNormal;
        //Start the thread.
        objThread.Start(command);
    }
    catch (ThreadStartException objException)
    {
        // Log the exception
    }
    catch (ThreadAbortException objException)
    {
        // Log the exception
    }
    catch (Exception objException)
    {
        // Log the exception
    }
}

string cmdStr = @" ""C:\Program Files (x86)\Microsoft Visual Studio 9.0\VC\vcvarsall.bat""
                  cd ""C:\Users\Johan\Documents\Visual Studio 2008\Projects\CCOSApp""
                  msbuild /target:Build /p:BuildingProject=true;OutDir=C:\Temp\build 
                  ccosapp.sln";
new VsFunctions().ExecuteCommandAsync(cmdStr);

Answer 1

我带来了这个解决方法：

StreamWriter w = new StreamWriter(@"C:\temp\publish.bat");
w.WriteLine(@"call ""C:\Program Files (x86)\Microsoft Visual Studio 9.0\VC\vcvarsall.bat""");
w.WriteLine(@"call cd ""C:\Users\Johan\Documents\Visual Studio 2008\Projects\CCOSApp""");
w.WriteLine(@"call msbuild /target:Build /p:BuildingProject=true;OutDir=C:\Temp\build ccosapp.sln");
w.Close();

System.Diagnostics.Process proc = new System.Diagnostics.Process();
ProcessStartInfo psi = new ProcessStartInfo(@"publish.bat");
psi.WorkingDirectory = @"C:\temp\";
proc.StartInfo = psi;
proc.Start();

我创建了一个.bat文件。
我在里面写命令。
最后，我将.bat文件作为Process启动。

Answer 2

C：\ Program'未被识别为内部或外部命令，可操作程序或批处理文件。

您收到此错误，因为您的路径中有Program和File

之间的空格

尝试在路径的开头和结尾放置双引号

Answer 3

尝试通过

将目录更改为“C：\ Program Files（x86）\ Microsoft Visual Studio 9.0 \ VC \”，而不是传递可执行文件的整个路径。

oInfo.WorkingDirectory = @"C:\Program Files (x86)\Microsoft Visual Studio 9.0\VC\";

然后只需调用vcvarsass.bat

希望有帮助

Answer 4

使用Arguments

的StartInfo属性时是否有效

Process cmd = new Process();
cmd.StartInfo.CreateNoWindow = false;
cmd.StartInfo.UseShellExecute = false;
cmd.StartInfo.FileName = @"C:\Program Files (x86)\Microsoft Visual Studio 9.0\VC\vcvarsall.bat";
cmd.StartInfo.Arguments = @"msbuild C:\Users\Johan\Documents\Visual Studio 2008\Projects\PRJAPP\PRJAPP.sln";
cmd.Start();
cmd.WaitForExit();

就像在这个例子中一样：Using cmd.exe from C#

如何在c＃代码中将参数传递给命令提示符？

4 个答案: