Question

我的表格中有一列由多个值组成，由-分隔。

示例：

STB-123456789-010116

我想得到：

col1    col2        col3
STB     123456789   010116

这3个字段将存储在3列的另一个数据库中。

如何获得所需的输出？

Answer 1

SELECT PARSENAME(REPLACE('STB-123456789-010116','-','.'),3),PARSENAME(REPLACE('STB-123456789-010116','-','.'),2),
PARSENAME(REPLACE('STB-123456789-010116','-','.'),1)

Answer 2

一种方法是使用内置string functions的Left，SubString，Right，CharIndex和Reverse：

DECLARE @S varchar(100) = 'STB-123456789-010116'

SELECT  LEFT(@S, CHARINDEX('-', @S) - 1) As LeftSide,
        SUBSTRING(@S, CHARINDEX('-', @S) + 1, LEN(@S) - CHARINDEX('-', REVERSE(@S)) -  CHARINDEX('-', @S)) As Middle,
        RIGHT(@S, CHARINDEX('-', REVERSE(@S)) - 1) As RightSide




LeftSide    Middle      RightSide
---------------------------------
STB         123456789   010116

Answer 3

您也可以使用XML：

DECLARE @x xml

;WITH cte AS (
SELECT  1 as id,
        'STB-123456789-010116' as some_column
UNION ALL
SELECT  2,
        'STB-9876543210-0918677'
)

SELECT @x = (
    SELECT CAST('<i id="' + CAST(id as nvarchar(10)) +'"><a>' + REPLACE(some_column,'-','</a><a>') + '</a></i>' as xml)
    FROM cte
    FOR XML PATH('')
)

SELECT  t.v.value('@id','int') as id,
        t.v.value('a[1]','nvarchar(100)') as col1,
        t.v.value('a[2]','nvarchar(100)') as col2,
        t.v.value('a[3]','nvarchar(100)') as col3
FROM @x.nodes('/i') as t(v)

输出：

id  col1    col2        col3
1   STB     123456789   010116
2   STB     9876543210  0918677

SPLIT sql server中的一个列由＆＃39; - ＆＃39;

3 个答案: