Simple Flask应用程序 - 无法连接到localhost上的数据库?

时间:2016-06-16 10:37:56

标签: python mysql sqlite flask

我正在尝试遵循本教程:
http://code.tutsplus.com/tutorials/creating-a-web-app-from-scratch-using-python-flask-and-mysql--cms-22972

我有Web应用程序出现,我可以在页面之间浏览,当我在填写详细信息后单击“注册”时,我在python中收到此错误:

ERROR:__main__:Exception on /signUp [POST]
OperationalError: (2003, "Can't connect to MySQL server on 'localhost' (10061)")

我不确定这里发生了什么,我在app.py根文件夹中有一个名为“BucketList.db”的数据库。

有没有办法找出被卡住的地方?或者为什么它无法连接到数据库?我可以使用Sqlite直接连接到数据库,这一切看起来都很好,所以可能是不正确的,它是如何通过localhost访问的?

任何帮助/指导将不胜感激!谢谢!

from flask import Flask, render_template, json, request
from flask_mysqldb import MySQL
from werkzeug import generate_password_hash, check_password_hash

mysql = MySQL()
app = Flask(__name__)

# MySQL configurations
app.config['MYSQL_DATABASE_DB'] = 'BucketList'
app.config['MYSQL_DATABASE_HOST'] = 'localhost'
app.config['MYSQL_DATABASE_PORT'] = '5002'
mysql.init_app(app)

@app.route('/')
def main():
    return render_template('index.html')

@app.route('/showSignUp')
def showSignUp():
    return render_template('signup.html')


@app.route('/signUp',methods=['POST','GET'])
def signUp():
    try:
        _name = request.form['inputName']
        _email = request.form['inputEmail']
        _password = request.form['inputPassword']

        # validate the received values
        if _name and _email and _password:

            # All Good, let's call MySQL
            conn = mysql.connect()
            cursor = conn.cursor()
            _hashed_password = generate_password_hash(_password)
            cursor.callproc('sp_createUser',(_name,_email,_hashed_password))
            data = cursor.fetchall()

            if len(data) is 0:
                conn.commit()
                return json.dumps({'message':'User created successfully !'})
            else:
                return json.dumps({'error':str(data[0])})
        else:
            return json.dumps({'html':'<span>Enter the required fields</span>'})

    except Exception as e:
        return json.dumps({'error':str(e)})
    finally:
        cursor.close() 
        conn.close()

if __name__ == "__main__":
    app.run(port=5002)

2 个答案:

答案 0 :(得分:1)

您可以尝试避免在finally子句中再次连接。只需编写conn.close()和cursor.close()。它应该可以解决你的问题。

答案 1 :(得分:0)

这是我使用scrineym建议的Sqlite实现工作的代码。它的工作原理是你有一个进入并提交到数据库的应用程序。

现在我唯一的问题是,当我提交/获取错误/没有写入字段数据时,json部分无法正常工作!至少有一个解决方案适用于原始问题!

from flask import Flask, render_template, json, request
from werkzeug import generate_password_hash, check_password_hash
import sqlite3
from flask import g 

DATABASE = 'BucketList.db'

#mysql = MySQL()
app = Flask(__name__)

@app.route('/')
def main():
    return render_template('index.html')

@app.route('/showSignUp')
def showSignUp():
    return render_template('signup.html')


@app.route('/signUp',methods=['POST','GET'])
def signUp():
    _name = request.form['inputName']
    _email = request.form['inputEmail']
    _password = request.form['inputPassword']

    # validate the received values
    if _name and _email and _password:
        print _name, _email

        db = g._database = sqlite3.connect(DATABASE)
        cursor = get_db().cursor()
        print "Database opened"

        _hashed_password = generate_password_hash(_password)
        print _hashed_password

        _userid = str(_name) + str(_hashed_password[0:4])
        db.execute('INSERT INTO tbl_user VALUES (?,?,?,?)',(_userid,_name,_email,_hashed_password))
        db.commit()

        data = cursor.fetchall()
        if len(data) is 0:
            conn.commit()
            return json.dumps({'message':'User created successfully !'})
        else:
            return json.dumps({'error':str(data[0])})
    else:
        return json.dumps({'html':'<span>Enter the required fields</span>'})

        cursor.close() 
        db.close()

        print "Database closed"

    "Print here"

if __name__ == "__main__":
    app.run(port=5002)