Question

如何以angular2重新加载页面。
在通过网络搜索时，我得到了一个代码"this._router.renavigate()"来重新加载页面，但看起来它不适用于最新版本的angular2。
另一种方式是'window.location.reload()'，但这不是做角度的方式。

Answer 1

如果您真的想重新加载页面，则需要在角度区域外运行location.reload（）

this.zone.runOutsideAngular(() => {
    location.reload();
});

用RC6测试

完整示例

import { Component, NgZone } from "@angular/core";

@Component({        
    templateUrl: "template.html"    
})
export class ReloadComponent{
    constructor(
        private zone: NgZone) {
    }

    reloadPage() { // click handler or similar
        this.zone.runOutsideAngular(() => {
            location.reload();
        });
    }
}

Answer 2

对于partial，有办法编写自己的函数

   public renavigate(): void {
   let params: Object = {};
   Object.assign(params, this.routeParams.params);
   params['ref'] = (params['ref'] === ref) ? ref + new Date().getTime() : ref;
   this.router.navigate(['Foo', params]);
   }

Answer 3

这对我有用：

#include <iostream>
#include <fstream>
#include <ctime>
#include <iomanip>
#include <sstream>
#include <thread>

int main()
{
    std::wstring updateTime(L"Thu Dec 14 15:06:00 2016");
    std::wstring updatePeriod(L"30");
    std::string timeUpdate(updateTime.begin(), updateTime.end());
    std::istringstream ss{ timeUpdate };
    struct tm dateUp ={};
    ss >> std::get_time(&dateUp, "%a %b %d %X %Y");

    std::time_t t1 = std::mktime(&dateUp);


    //time_t t1 = std::mktime(&dateUp);  // Contine data la care se porneste    testul
    int periodUpdate = std::stoi(updatePeriod); // Contine numarul de minute 
    std::cout <<"Data inainte de a se adauga minutele = "<< 1900 + dateUp.tm_year << " " << dateUp.tm_mon << " " << dateUp.tm_mday << " " << dateUp.tm_hour << ":" << dateUp.tm_min << "\n\n";

    // Adaug minutele la data la care se porneste testul si apoi refac structura de tip time_t (minutele se convertesc automat in ore, zile..)
    dateUp.tm_min += periodUpdate;
    t1 = std::mktime(&dateUp);
    std::cout <<"Data dupa ce s-au adaugat minutele = "<< 1900 + dateUp.tm_year << " " << dateUp.tm_mon << " " << dateUp.tm_mday << " " << dateUp.tm_hour << ":" << dateUp.tm_min << "\n\n";

    // Retin data curenta a calculatorului
    time_t now = time(NULL); 
    struct tm now_tm = *localtime(&now);
    time_t t2 = std::mktime(&now_tm);

    std::cout << "Data curenta = "<<1900 + now_tm.tm_year << " " << now_tm.tm_mon << " " << now_tm.tm_mday << " " << now_tm.tm_hour << ":" << now_tm.tm_min << "\n\n";

    //Compar cele 2 date. Pentru a se face update programat diferenta trebuie sa fie pozitiva. Adica data actuala sa fie mai mare decat data la care ar trebui sa se faca update
    double diff = difftime(t2, t1);
    std::cout << diff << "\n";
}

Answer 4

我遇到了同样的问题，这对我有用：

＆＃13;

import { Location } from '@angular/common';

constructor(private location: Location) {}

ngOnInit() { this.load(); }

load() {
  this.location.reload();
}

＆＃13;

Answer 5

使用

提高知名度的重要性

  actions: {
    willTransition() {
      let records = this.get('controller.records');
      records.setEach('selected', false); 
    }
  }

使用户体验更好

Answer 6

location.reload（）将重新加载页面。

如何在angular2中重新加载页面

6 个答案: