我是jquery和jqgrid的新手。您能否通过示例帮助我理解并实现jqgrid中的分页。下面是到目前为止编写的代码。我有所有选项集（pager，rowNum，rowList，loadonce：true）
<html xmlns="http://www.w3.org/1999/xhtml" >
<head runat="server">
<title></title>
<script src="Scripts/jquery.js" type="text/javascript"></script>
<script src="Scripts/jquery-1.11.0.js" type="text/javascript"></script>
<script src="Scripts/jquery.jqGrid.min.js" type="text/javascript"></script>
<link href="Scripts/jquery-ui-1.10.3.custom.css" rel="stylesheet" type="text/css" />
<script src="Scripts/jquery-ui.js" type="text/javascript"></script>
<!-- The jQuery UI theme extension jqGrid needs -->
<link href="Scripts/ui.jqgrid.css" rel="stylesheet" type="text/css" />
<script language="javascript" type="text/javascript">
$(document).ready(function() {
LoadEmployees();
});
var ChargeItems = [];
var NewBatchItems = [];
function LoadEmployees() {
debugger;
$("#grps").jqGrid("clearGridData", true);
$("#grps").GridUnload();
$('#grps').jqGrid({
datatype: function() {
debugger;
jQuery.ajax({
type: 'POST',
contentType: 'application/json;charset=utf-8',
datatype: 'json',
data: {},
url: 'JQueryGridExample2.aspx/GetEmployees',
success: function(responseData) {
debugger;
ChargeItems = [];
var NewBatchItems = JSON.parse(responseData.d);
for (var i = 0; i < NewBatchItems.length; i++) {
var item = NewBatchItems[i];
ChargeItems.push({ "EmployeeID": item.EmployeeID, "EmployeeName": item.EmployeeName, "DepartmentName": item.DepartmentName, "DesignationName": item.Designation, "Salary": item.Salary });
}
debugger;
var grid = $("#grps")[0];
grid.addJSONData(ChargeItems);
},
error: function() {
alert("Error with AJAX callback");
}
});
},
colNames: ['EmployeeID', 'EmployeeName', 'DepartmentName', 'Designation', 'Salary'],
colModel: [{ name: 'EmployeeID', index: 'EmployeeID', hidden: true, width: 100 }, { name: 'EmployeeName', index: 'EmployeeName', sortable: false, width: 250 }, { name: 'DepartmentName', sortable: false, index: 'Department', width: 250 }, { name: 'DesignationName', sortable: false, index: 'DesignationName', width: 250 }, { name: 'Salary', index: 'Salary', sortable: false, width: 100}],
height: "auto",
grouping: false,
refreshtext: "refresh",
MultiSelect: false,
pager: jQuery('#pager'),
rowNum: 5,
rowList: [5, 10, 15, 20, 30],
loadonce: true,
viewrecords: true,
recordtext: "View {0} - {1} of {2}",
emptyrecords: "No records to view",
loadtext: "Loading...",
pgtext : "Page {0} of {1}",
sortname: "EmployeeID",
sortorder: "asc",
jsonReader: {
repeatitems: false,
root: function(obj) { return obj; },
page: function(obj) { return $("#grps").jqGrid('getGridParam', 'page'); },
total: function(obj) { return Math.ceil(obj.length / $("#grps").jqGrid('getGridParam', 'rowNum')); },
records: function(obj) { return obj.length; }
},
caption: "Employee Details Report"
});
jQuery("#grps").jqGrid('navGrid', '#pager', { search: false, refresh: false, edit:false, add:false, del:false });
}
</script>
</head>
<body>
<form id="form1" runat="server">
<div>
<table id="grps" border="1"></table>
<div id="pager"></div>
</div>
</form>
</body>
</html>
[WebMethod]
public static object GetEmployees()
{
List<EmployeeVo> objEmpList = new List<EmployeeVo>();
EmployeeController objController = new EmployeeController();
objEmpList = objController.GetEmployeesList();
var jsonLabTests = (JsonConvert.SerializeObject(objEmpList));
return jsonLabTests;
}
答案 0 :(得分：0)
1.像你这样[WebMethod]：
[WebMethod]
[System.Web.Script.Services.ScriptMethod(ResponseFormat = System.Web.Script.Services.ResponseFormat.Json)]
public static List<EmployeeVo> GetEmployees()
{
List<EmployeeVo> objEmpList = new List<EmployeeVo>();
EmployeeController objController = new EmployeeController();
objEmpList = objController.GetEmployeesList();
return objEmpList;
}
2.然后只需复制\粘贴下面的代码就可以了：
<head runat="server">
<title></title>
<link rel="stylesheet" href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8.14/themes/redmond/jquery-ui.css" type="text/css" />
<link href="https://cdn.jsdelivr.net/jqgrid/4.6.0/css/ui.jqgrid.css" rel="stylesheet" />
<script type="text/javascript" src="http://code.jquery.com/jquery-1.10.2.min.js"></script>
<script type="text/javascript" src="http://code.jquery.com/ui/1.10.3/jquery-ui.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/jqgrid/4.6.0/js/i18n/grid.locale-en.js"></script>
<script src="https://cdn.jsdelivr.net/jqgrid/4.6.0/jquery.jqGrid.min.js"></script>
<script type="text/javascript">
$(function () {
GetData();
function GetData() {
$('#grps').jqGrid({
url: 'JQueryGridExample2.aspx/GetEmployees',
mtype: 'POST',
ajaxGridOptions: { contentType: "application/json" },
datatype: "json",
serializeGridData: function (postData) {
return JSON.stringify(postData);
},
loadonce: true,
jsonReader: {
root: function (obj) { return obj.d; },
page: function (obj) { return 1; },
total: function (obj) { return 1; },
records: function (obj) { return obj.d.length; },
id: '0',
cell: '',
repeatitems: false
},
datatype: "json",
height: "auto",
pager: jQuery('#pager'),
rowNum: 5,
rowList: [5, 10, 15, 20, 30],
colNames: ['EmployeeID', 'EmployeeName', 'DepartmentName', 'Designation', 'Salary'],
colModel: [{ name: 'EmployeeID', index: 'EmployeeID', hidden: true, width: 100 }, { name: 'EmployeeName', index: 'EmployeeName', sortable: false, width: 250 }, { name: 'DepartmentName', sortable: false, index: 'Department', width: 250 }, { name: 'DesignationName', sortable: false, index: 'DesignationName', width: 250 }, { name: 'Salary', index: 'Salary', sortable: false, width: 100 }],
caption: "Employees table"
});
jQuery("#grps").jqGrid('navGrid', '#pager', { search: false, refresh: false, edit: false, add: false, del: false });
}
});
</script>
</head>
<body>
<form id="form1" runat="server">
<table id="grps" border="1"></table>
<div id="pager"></div>
</form>
</body>
答案 1 :(得分：0)
的JavaScript
function abc(){
jQuery("#pnlGridData").jqGrid({
datatype: function (postdata) {
params.PageSize = postdata.rows;
params.PageIndex = postdata.page;
$.ajax({
url: "abc.aspx/GetData",
data: JSON.stringify({ 'params': params }),
dataType: "json",
type: "POST",
contentType: "application/json; charset=utf-8",
success: function(jsondata){
var thegrid = jQuery("#pnlGridData")[0];
thegrid.addJSONData(JSON.parse(jsondata.d))
}
//failure: reportError
});
},
colNames: ['ID', 'Name'],
colModel: [
{ name: 'ProviderCredentials', index: 'ID', width: 35, align: 'center', sorttype: "int", sortable: false, resizable: false, hidden: true },
{ name: 'ProviderCredentialsName', index: 'Name', width: 25, align: 'center', sorttype: "int", sortable: false, resizable: false },
],
rowNum: 5,
rowList: [5, 10, 15, 20, 30],,
autoWidth: true,
pager: "#JQGridData_Navigation",
viewrecords: true,
onPaging: function (pgButton) {
return Paging("pnlGridData", "JQGridData_Navigation", currentpageindex, pgButton);
},
rowNum: 0,
editurl: "clientArray"
});
}
function Paging(GridName, PagerControlName, LastVisitedPage, pgButton) {
if (pgButton != "user") {
PagerButton = pgButton.split('_');
NavDirection = PagerButton[0];
}
else
NavDirection = pgButton;
var totalpages2 = parseInt(document.getElementById("sp_1_" + PagerControlName).innerHTML.replace(',', ''));
if (NavDirection.toLowerCase() == "user") {
var newpageindex2 = $("#pg_" + PagerControlName + " .ui-pg-input").val();
if (isNaN(newpageindex2) || newpageindex2 < 1 || totalpages2 < newpageindex2) {
alert("Invalid page number");
$("#" + GridName).setGridParam({ page: LastVisitedPage });
$("#pg_" + PagerControlName + " .ui-pg-input").val(LastVisitedPage);
return 'stop';
}
}
}
Html代码
<table width="100%" align="center" id="trGrid" runat="server">
<tr>
<td></td>
</tr>
<tr>
<td>
<div id="divGridData" style="text-align:center; display: none;">
<table id="pnlGridData">
</table>
<div id="JQGridData_Navigation">
</div>
</div>
<div id="JQProviderCredentials_msgNoRecord" class="Emptry_Row_Gridview" style="display: none;">
No Record Found
</div>
</td>
</tr>
</table>
背后的代码
[WebMethod]
public static string GetData(object params)
{
try
{
int totalRecords = 0;
int PageSize = 0;
int totalpages = 0;
int PageIndex = 0;
Dictionary<string, object> paramsobject = (Dictionary<string, object>)params;
if (Convert.ToInt16(paramsobject["PageIndex"]) == 0)
PageIndex = 1;
else
PageIndex = Convert.ToInt16(paramsobject["PageIndex"]);
if (Convert.ToInt16(paramsobject["PageSize"]) == 0)
PageSize = 10;
else
PageSize = Convert.ToInt16(paramsobject["PageSize"]);
List<Dictionary<string, object>> lstData = new List<Dictionary<string, object>>();
var jsonSerializer = new JavaScriptSerializer();
DataSet objDataSet = new DataSet();
objDataSet =//get data
totalRecords = Convert.ToInt32(objDataSet.Tables[0].Rows[0]["TotalRowCount"].ToString());
totalpages = totalpages = (Convert.ToInt32(totalRecords) / Convert.ToInt32(PageSize)) + (Convert.ToInt32(totalRecords) % Convert.ToInt32(PageSize) > 0 ? 1 : 0);
lstData = GetTableRows(objDataSet.Tables[0]);
var data = new
{
total = totalpages,
page = PageIndex,
records = totalRecords,
rows = lstData
};
return jsonSerializer.Serialize(data);
}
catch (Exception ex)
{
ProcessException(ex, true);
throw;
}
}
public static List<Dictionary<string, object>> GetTableRows(DataTable dtData)
{
List<Dictionary<string, object>>
lstRows = new List<Dictionary<string, object>>();
Dictionary<string, object> dictRow = null;
foreach (DataRow dr in dtData.Rows)
{
dictRow = new Dictionary<string, object>();
foreach (DataColumn col in dtData.Columns)
{
dictRow.Add(col.ColumnName, dr[col]);
}
lstRows.Add(dictRow);
}
return lstRows;
}
现在只需要将Pagesize和PageIndex添加到您的存储过程中。
并获取数据。
答案 2 :(得分：0)
您应永远不要使用datatype定义为功能。您应该使用datatype: "json"，并指定url: 'JQueryGridExample2.aspx/GetEmployees'和ajaxGridOptions: { contentType: "application/json" }（或ajaxGridOptions: { contentType: "application/json;charset=utf-8" }）作为jqGrid的选项。 jqGrid将为您发出相应的Ajax请求。
此外，您应该修复WebMethod的代码并直接返回List<EmployeeVo>，而不是显式调用JsonConvert.SerializeObject。重要的是要理解ASP.NET在内部为您 将返回数据序列化为JSON或基于请求的contentType进行XML序列化。换句话说，您应该删除代码行var jsonLabTests = (JsonConvert.SerializeObject(objEmpList)); return jsonLabTests;，然后使用return objEmpList;代替。