Question

to_chr函数应该返回加密数组但转换为字符。我尝试了很多东西并评论了那些没有用的东西。

class Encrypt
  def initialize(code, string)
    @code = code
    @string = string
    @encrypted = []
  end

  def to_byte
    @string.each_byte do |c|
      @encrypted.push(c + @code)
    end
    print @encrypted
  end

  def to_chr
    n = @encrypted.length
    # n.times do |i|
    #   @encrypted.push(i.chr)
    # end
    print @encrypted[0].chr

    # @encrypted.each do |x|
    #   @encrypted.push(x.chr)
    # end
    # print @encrypted
  end
end

goop = Encrypt.new(2, "hello")
goop.to_chr
#=> in `to_chr': undefined method `chr' for nil:NilClass (NoMethodError)

Answer 1

def to_chr
    @encrypted.each do |i|
      print i.chr
    end
    print "\n"
end

请务必在to_byte

之前致电to_chr

goop = Encrypt.new(2, "hello")
goop.to_byte
goop.to_chr

返回：

jgnnq

Answer 2

您创建了Encrypted方法的实例，但您设置了@code = 2，@string = "Hello"和@encrypted = []。因此，如果您致电@encrypted[0]，红宝石会返回nil。

所以你可以像这样修改你的课程：

class Encrypt
  def initialize(code, string)
    @code, @string, @encrypted = code, string, []
  end

  def to_byte
    @string.each_byte { |c| @encrypted << c + @code }
  end

  def to_chr
    to_byte if @encrypted.empty?

    @encrypted.map(&:chr)
  end
end

goop = Encrypt.new(2, "hello")
p goop.to_chr
# => ["j", "g", "n", "n", "q"]

我希望这会有所帮助

将数字数组转换为字符ruby

2 个答案: