Question

我正在努力克服我的一个PHP脚本中的错误。这是一个我无法解释的奇怪行为。请帮我。首先：

$php -v
PHP 7.0.7 (cli) (built: May 25 2016 18:40:26) ( NTS )

在我的脚本中，我运行了一个MySQL查询，该查询正在成功。其次我这样做：

 while ($z = mysqli_fetch_array($req)) {
            if (!isset($datenGraph[$z[0]])) {
                $datenGraph[$z[0]] = [];
        } //just fill the array with zeros before and after the result
            while (count($datenGraph[$z[0]]) < ($z[2] - 1)) {
                array_push($datenGraph[$z[0]], 0);
            } 
            array_push($datenGraph[$z[0]], (int)$z[3]);
        }
    foreach ($datenGraph as $key => &$value) {
        while (count($value) < 12) {
            array_push($value, 0);
        }
    }

但是上面的代码不是问题。在那里我创建了一个如下所示的数组（数组键 - >值，它包含数组）：

array (size=4)
  'Numerber1' => 
    array (size=12)
   0 => int 0     1 => int 0      2 => int 0      3 => int 0
   4 => int 2     5 => int 16     6 => int 0      7 => int 0      
   8 => int 0     9 => int 0      10 => int 0     11 => int 0
  'Number2' => 
    array (size=12)
   0 => int 0     1 => int 0     2 => int 0      3 => int 0
   4 => int 2     5 => int 7     6 => int 0      7 => int 0    
   8 => int 0     9 => int 0     10 => int 0     11 => int 0 
  'Number3' => 
   array (size=12)
  0 => int 0      1 => int 0     2 => int 0      3 => int 0
  4 => int 0      5 => int 8     6 => int 0      7 => int 0
  8 => int 0      9 => int 0     10 => int 0     11 => int 0
  'Number4' => 
    array (size=12)
  0 => int 0      1 => int 0     2 => int 0      3 => int 0  
  4 => int 0      5 => int 7     6 => int 0      7 => int 0 
  8 => int 0      9 => int 0     10 => int 0     11 => int 0

请注意，所有元组都不同（正确的数据）。 现在是棘手的部分。在评估此数组时，最后一个元组的内容会更改为前一个元组！无论数组中有多少元组。

以下是它的样子：

foreach ($datenGraph as $key => $value) {
                print_r($value);
            }

打印相同的最后2个元组：

   Array ( [0] => 0 [1] => 0 [2] => 0 [3] => 0 [4] => 2 [5] => 16 [6] => 0 [7] => 0 [8] => 0 [9] => 0 [10] => 0 [11] => 0 )
   Array ( [0] => 0 [1] => 0 [2] => 0 [3] => 0 [4] => 2 [5] => 7 [6] => 0 [7] => 0 [8] => 0 [9] => 0 [10] => 0 [11] => 0 )
   Array ( [0] => 0 [1] => 0 [2] => 0 [3] => 0 [4] => 0 [5] => 8 [6] => 0 [7] => 0 [8] => 0 [9] => 0 [10] => 0 [11] => 0 ) 
   Array ( [0] => 0 [1] => 0 [2] => 0 [3] => 0 [4] => 0 [5] => 8 [6] => 0 [7] => 0 [8] => 0 [9] => 0 [10] => 0 [11] => 0 )

下一个打印出与上面相同的错误。：

$valueSet2 = array_values($datenGraph);
foreach ($valueSet2 as $key => $value) {
            print_r($value);
        }

但会打印出正确的内容。

$valueSet2 = array_values($datenGraph);
function console_log( $data )
{
    echo '<script>';
    echo 'console.log(' . json_encode( $data ) . ')';
    echo '</script>';
}
console_log($valueSet2);

给予：[[0,0,0,0,2,16,0,0,0,0,0,0],[0,0,0,0,2,7,0,0,0,0,0,0],[0,0,0,0,0,8,0,0,0,0,0,0],[0,0,0,0,0,7,0,0,0,0,0,0]

从这里得到正确的结果（双json_encode）（获取字符串）：

$valueSet2 = json_encode(array_values($datenGraph));
console_log($valueSet2);

更令人困惑的是。请注意前两个示例中的json_encode打印正确的内容。现在我正在尝试这样做（下面几行）：

<?php
    $x=0;
        foreach ($datenGraph as $key => $value) {
            echo 'label: ' . '\'' . $key . '\'' . ' , ' . PHP_EOL;
            echo 'backgroundColor: ['  . 'randomColor() . ']' . ', ' . PHP_EOL;
            echo 'data: '  . json_encode($valueSet2[$x]) . PHP_EOL;
            if ($x < $keySetSize - 1){
                echo '}, {' . PHP_EOL;
                }
            $x=$x+1;
            }   
?>

在最后一次迭代中，我再次得到错误的元组，而不像之前使用json_encode的2个例子给出了期望的结果。我做错了什么？请帮忙。谢谢！

访问/使用PHP

0 个答案: