Question

我正在开发一些shell脚本。请帮帮我

我想用这样的FUNCTION突出显示特定的字符串。

#!/bin/bash
function echoWithColor(){
    local InputString=${1}
    tput bold;tput setaf 2   # make words color to bright green
    echo ${InputString}
    tput sgr0                # make words color to default
}

echoWithColor "Hello everyone!"

这有效，但我想在行尾添加一些空白（空格文本），如

echo -n "Input your age : "; read AGE

[root @ mycomputer scripts]＃。/ script.sh

输入您的年龄：9999

但

#!/bin/bash
function echoWithColor(){
    local InputString=${1}
    tput bold;tput setaf 2   # make words color to bright green
    echo ${InputString}
    tput sgr0                # make words color to default
}

echoWithColor "-n Input your age : "; read AGE

[root @ mycomputer scripts]＃。/ script.sh

输入您的年龄：9999

都能跟得上

#!/bin/bash
function echoWithColor(){
    local InputString=${1}
    tput bold;tput setaf 2   # make words color to bright green
    echo ${InputString}
    tput sgr0                # make words color to default
}

echoWithColor "-n \"Input your age : \""; read AGE

[root @ mycomputer scripts]＃。/ script.sh

＆＃34;输入您的年龄：＆＃34; 9999

逃逸？不。

如何在行尾添加空白文字？

Answer 1

只需添加空间＆＃39; ＆＃39;在echo ${InputString}命令中的函数如下所示

#!/bin/bash
function echoWithColor(){
    local InputString=${1}
    tput bold;tput setaf 2   # make words color to bright green
    echo ${InputString}' ' 
    tput sgr0                # make words color to default
}

echoWithColor "-n Input your age : "; read AGE

Answer 2

这是因为您没有引用变量：

var="    my value    "
echo $var without quotes   # writes: my value without quotes
echo "$var with quotes"    # writes:    my value     with quotes

由于您希望将多个字符串传递给echo（-n和Input your age），因此您应该重写该函数以获取多个参数（"$@"）而不是一个（$1） {1}}），然后确保在使用它们时引用：

#!/bin/bash
echoWithColor(){
    local InputStrings=( "$@" ) 
    tput bold;tput setaf 2   # make words color to bright green
    echo "${InputStrings[@]}"
    tput sgr0                # make words color to default
}

echoWithColor -n "Input your age: "

现在echoWithColor与echo完全相同，并保留您传递给它的所有空格。

带有双引号的Shell脚本函数参数，即ECHO命令的SIGN

2 个答案: