Question

我想比较两列page_entry＆amp; exit_page如果两个真值均为1则反弹。

Page_entry |  exit_page | Bounce 
    1             1        true
    0             1        false 
   etc           etc       ......

这是我提出的，它只显示了真正的价值

select hit_id,visit_num,
    CASE 

        WHEN entry_page = exit_page
        THEN 'True'
        ELSE 'False'

    END as Bounce
FROM [dbo].[Primary]
WHERE entry_page = exit_page
END

但现在我需要写一个类似

的计算

SUM(IF Bouce = TRUE THEN 1 ELSE 0 END)/page_visit

Answer 1

你正在寻找这样的东西吗？：

select hit_id,visit_num,
    SUM (CASE entry_page 
        WHEN exit_page THEN 1
        ELSE 0      
        END)/page_visit as ratio
FROM [dbo].[Primary]
group by hit_id,visit_num,page_visit ;

Answer 2

CASE WHEN entry_page = 1 AND exit_page = 1 THEN 'True' ELSE 'False' END as 'BounceAnswer'

SUM(CASE WHEN entry_page = 1 AND exit_page = 1 THEN 1 ELSE 0 END) as 'BounceCount'

Answer 3

选择hit_id，visit_num， SUM（CASE entry_page 当exit_page那么1 当entry_page那么1 ELSE 0
END）/ visit_num作为比率来自[dbo]。[小学] 按hit_id，visit_num，entry_page分组;

这让我非常感谢!!!!!

SQL - 比较两列找到真值并使用IF计算中的值

3 个答案: