Question

对于我的生活，我似乎无法用我的javascript找到问题。 Firebug正在吐出以下错误：

missing ) after argument list
[Break on this error] $.getJSON('http://local.yahooapis.co... results +'&output=json&callback=?',\n

这是我的代码：

function getLocationJSON(fooBar) {

 var appid = 'RvkxtGN.OtlDnsdkjsdP_DsOD3xXzFlW6LL6u3y3wTcW4zWZVgQL9O14X78ZoBY9c-';
 var results = 5;
 var query = 'pizza';
 var lat;
 var lon;

 $('#whereLocationSelector').click(function() {

function setDisplay(text) {
  $('#whereLocationSelector').empty().append(text);
}

jQT.updateLocation(function(coords){
  if (coords) {
    setDisplay('Location Acquired!');
    lat = coords.latitude;
    lon = coords.longitude;
  } else {
    setDisplay('Device not capable of geo-location.');
  }
});

}

$.getJSON('http://local.yahooapis.com/LocalSearchService/V3/localSearch?appid=' + appid   + '&query=' + query + '&latitude=' + lat +'&longitude=' + lon + '&results=' + results + '&output=json&callback=?',
function(funWorld) {
  console.log(funWorld);
});  
}

对于将来自行调试此方法的任何建议，我们将不胜感激。

Answer 1

您需要}之前使用});

$.getJSON('http://local.yahooapis.com/LocalSearchService/V3/localSearch?appid=' + appid   + '&query=' + query + '&latitude=' + lat +'&longitude=' + lon + '&results=' + results + '&output=json&callback=?', line

即替换

}

$.getJSON('http://local.yahooapis.com/LocalSearchService/V3/localSearch?appid=' + appid   + '&query=' + query + '&latitude=' + lat +'&longitude=' + lon + '&results=' + results + '&output=json&callback=?',
function(funWorld) {
  console.log(funWorld);
});  
}

用

});

$.getJSON('http://local.yahooapis.com/LocalSearchService/V3/localSearch?appid=' + appid   + '&query=' + query + '&latitude=' + lat +'&longitude=' + lon + '&results=' + results + '&output=json&callback=?',
function(funWorld) {
  console.log(funWorld);
});  
}

Answer 2

你应该把你的功能放在外面。对于

$('#whereLocationSelector').click(function() {

结束标记不正确。我已经解决了以下问题：

function getLocationJSON(fooBar) {

 var appid = 'RvkxtGN.OtlDnsdkjsdP_DsOD3xXzFlW6LL6u3y3wTcW4zWZVgQL9O14X78ZoBY9c-';
 var results = 5;
 var query = 'pizza';
 var lat;
 var lon;

 $('#whereLocationSelector').click(function() {

function setDisplay(text) {
  $('#whereLocationSelector').empty().append(text);
}

jQT.updateLocation(function(coords){
  if (coords) {
    setDisplay('Location Acquired!');
    lat = coords.latitude;
    lon = coords.longitude;
  } else {
    setDisplay('Device not capable of geo-location.');
  }
});

});

$.getJSON('http://local.yahooapis.com/LocalSearchService/V3/localSearch?appid=' + appid   + '&query=' + query + '&latitude=' + lat +'&longitude=' + lon + '&results=' + results + '&output=json&callback=?',
function(funWorld) {
  console.log(funWorld);
});  
}

javascript firebug错误帮助

2 个答案: