我尝试使用Spring Data存储库并尝试设置一个简单的存储库已经有两天了。
我使用CrudRepository
我有我的实体类
这是我的XML,突出显示的行在Web浏览器中给出了错误
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://www.springframework.org/schema/beans"
xmlns:jpa="http://www.springframework.org/schema/data/jpa"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:repository="http://www.springframework.org/schema/data/repository"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd
http://www.springframework.org/schema/data/repository
http://www.springframework.org/schema/data/repository/spring-repository.xsd
http://www.springframework.org/schema/data/jpa
http://www.springframework.org/schema/data/jpa/spring-jpa.xsd">
<bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="com.mysql.jdbc.Driver"/>
<property name="url" value="jdbc:mysql://localhost/test"/>
<property name="username" value="root"/>
<property name="password" value=""/>
</bean>
<jpa:repositories base-package="com.mydata"/>
<bean id="jpaVendorAdapter" class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="showSql" value="true"/>
<property name="generateDdl" value="true"/>
<property name="database" value="test"/>
</bean>
<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="dataSource"/>
<property name="jpaVendorAdapter" ref="jpaVendorAdapter"/>
<!-- spring based scanning for entity classes-->
<property name="packagesToScan" value="com.mydata"/>
</bean>
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager"/>
</beans>
当我访问我在其中启动此bean类的控制器时,我在Web浏览器中出现以下错误
Initialization of bean failed; nested exception is org.springframework.beans.ConversionNotSupportedException: Failed to convert property value of type 'java.lang.String' to required type 'org.springframework.orm.jpa.vendor.Database' for property 'database'; nested exception is java.lang.IllegalStateException: Cannot convert value of type [java.lang.String] to required type [org.springframework.orm.jpa.vendor.Database] for property 'database': no matching editors or conversion strategy found
由于XML中的行属性名称=“数据库”值=“测试”
而发生此错误沙赫扎德
答案 0 :(得分:1)
JavaDoc中指示database
属性采用数据库类型,而不是名称。
一般情况下,我建议更多地考虑一下Spring Boot及其JPA支持(在此处查找a guide),因为它可以帮助您完成所有样板配置设置。
答案 1 :(得分:0)
您是否尝试过MYSQL数据库值?我认为Spring应该将其隐式转换为Database.MYSQL
<bean id="jpaVendorAdapter" class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="showSql" value="true"/>
<property name="generateDdl" value="true"/>
<property name="database" value="MYSQL"/>
</bean>
或Spring Boot bean定义
@Bean
public JpaVendorAdapter jpaVendorAdapter() {
HibernateJpaVendorAdapter hibernateJpaVendorAdapter = new HibernateJpaVendorAdapter();
hibernateJpaVendorAdapter.setShowSql(true);
hibernateJpaVendorAdapter.setGenerateDdl(true);
hibernateJpaVendorAdapter.setDatabase(Database.MYSQL);
return hibernateJpaVendorAdapter;
}