Question

我正在尝试根据他们在主场和客场的时间来计算每支球队的得分和进球数之间的净胜球。但问题是我收到了这个错误：

无法对包含聚合或子查询的表达式执行聚合函数。

我注释掉了“Goal_Difference”代码，想知道导致此问题的原因并且可以修复。谢谢

ALTER VIEW League_Table
AS
SELECT SUM(
    CASE
        WHEN t.TeamID = f.HomeTeamID THEN f.HomeScore
        -- Home Fixture
        WHEN t.TeamID = f.AwayTeamID THEN f.AwayScore
        -- Away Fixture
        END
        ) AS Goals_Scored,

    SUM(
    CASE
        WHEN t.TeamID = f.HomeTeamID THEN f.AwayScore
        -- Home Fixture
        WHEN t.TeamID = f.AwayTeamID THEN HomeScore
        -- Away Fixture
        END
        ) AS Goals_Against
     --   SUM(
        --  CASE
        --  WHEN t.TeamID = f.HomeTeamID THEN       
        --      CASE
        --      WHEN f.HomeScore IS NOT NULL THEN SUM(f.HomeScore) - SUM(f.AwayScore)
        --  -- Home Fixture
        --      END
        --  WHEN t.TeamID = f.AwayTeamID THEN 
        --      CASE
        --      WHEN f.AwayScore IS NOT NULL THEN SUM(f.AwayScore) - SUM(f.HomeScore)
        --  -- Away Fixture
        --      END
        --  END
        --) AS Goal_Difference

FROM dbo.Team t
--Season TBC
INNER JOIN dbo.Fixture f ON t.TeamID IN (f.HomeTeamID, f.AwayTeamID)
GROUP BY t.TeamName


GO

SELECT *  
FROM League_Table lt
ORDER BY Points DESC--, Goal_Difference;

Answer 1

将Goal_Difference更改为：

        SUM(
      CASE
      WHEN t.TeamID = f.HomeTeamID THEN       
          CASE
          WHEN f.HomeScore IS NOT NULL THEN f.HomeScore - f.AwayScore
      -- Home Fixture
          END
      WHEN t.TeamID = f.AwayTeamID THEN 
          CASE
          WHEN f.AwayScore IS NOT NULL THEN f.AwayScore - f.HomeScore
      -- Away Fixture
          END
      END
    ) AS Goal_Difference

如果您在CASE之前汇总，则无法在WHEN中再次汇总，而sum(sum(..变为print，这是不允许的。我认为这不是你想要的，所以我只是删除了内部总和。

无法对表达式执行聚合函数

1 个答案: