在gsub中使用通配符

Question

我想做这样的事情：

"String with text and $abc$ and $def$ and so on... ".gsub("$*$", "replaceText")

导致

"String with text and replaceText and replaceText and so on... "

但我不知道像*这样的通配符是如何工作的。

Answer 1

您可以将regex用于此目的

"String with text and $abc$ and $def$ and so on... ".gsub(/\$\w+\$/, "replaceText")
#=> "String with text and replaceText and replaceText and so on... "

请记住，你需要逃避$

Answer 2

出于好奇：一个人是否有更多的分隔符（不仅仅是美元符号），她可能会使用back-references：

str = "String with text and $abc$ and *def* and so on... "
str.gsub(/(?<delim>[$*]).*?\k<delim>/, "replaceText")
#⇒ "String with text and replaceText and replaceText and so on... "

请注意，在[]内，无需转义$（*。）

Answer 3

"String with text and $abc$ and $def$ and so on... ".gsub(/\$\w+\$/, "replaceText")

在http://rubular.com/

中尝试\ $ \ w + \ $

http://rubular.com/r/ZbgdVQvDGb