Question

基本上我要做的是根据共同的兴趣来建议人。

我有一个用户表（id，username，firstname，lastname等）

我有一张Interested_People表，其中存储了UserID + Interested_in。

我有一个联系人列表，其中存储了彼此相加的人。（user1，user2，accepted [1,0]）

我想要的是选择不是我朋友的*用户表，他们对我也有同样的兴趣。

我在互联网上搜索了很多但却找不到这样的东西。

Here i do have created a query and it does exactly what I want. But it is very slow. Even it takes 16 to 20 second to output in PHPMyAdmin in my local machine. Now I Kindly request you guys if you can edit my query a bit and make it bandwidth & time efficient.

SELECT * 
FROM   users 
WHERE  id IN(SELECT userid 
             FROM   interested_people 
             WHERE  interested_in IN(SELECT interested_in 
                                     FROM   interested_people 
                                     WHERE  userid = [userid]) 
                    AND id NOT IN(SELECT user1 AS my_friends_userid 
                                  FROM   contactlist f 
                                  WHERE  f.user2 = [userid] 
                                    AND accepted = 1 
                                  UNION 
                                  SELECT user2 AS my_friends_userid 
                                  FROM   contactlist f 
                                  WHERE  f.user1 = [userid] 
                                    AND accepted = 1)) 
       AND id != [userid] 
ORDER  BY Rand () 
LIMIT  0, 10;

此查询中的[Userid]是在线用户的ID。就像在线我的ID一样。

此查询建议10个随机用户不是我的朋友并且与我有相同的兴趣。但非常懒散。

提前致谢！

Answer 1

您的问题表明自我加入可以吸引具有共同兴趣的用户。然后，not exists以避免联系人列表。以下列出了具有共同兴趣的用户列表，按共同兴趣的数量排序：

select ip2.userid, count(*) as numInCommon
from interested_People ipme join
     interested_People ip2
     on ipme.interested_in = ip2.interested_in and
        ipme.userid = $UserId and  -- Your user id goes here
        ip2.userid <> ipme.userid
where not exists (select 1 
                  from contactlist cl
                  where cl.user1 = ipme.userid and cl.user2 = ip2.userid and
                        cl.accepted = 1
                 ) and
      not exists (select 1 
                  from contactlist cl
                  where cl.user1 = ip2.userid and cl.user2 = ipme.userid and
                        cl.accepted = 1
                 )
group by ip2.userid;

建议用户根据共同的兴趣 - MySql查询

1 个答案: