Question

$scope.addUserJson = $scope.adduser;

console.log($scope.addUserJson);

输出

Object {"username":"Mik911","firstname":"Mike","lastname":"Angel","email":"mik@gmail.com"}

$scope.usergroup = $scope.usergroupmodel;

console.log($scope.usergroup);

输出

[Object{"grpid":"1","username":"Vikram911","firstname":"Vikram","lastname":"Doe","email":"vik@gmail.com","gender":"Male", "description":"BLAH BLAH","phone":"5858585"},{"grpid":"2","username":"Varun091","firstname":"Varun","lastname":"Doe", "email":"varun@gmail.com","gender":"Male","description":"BLAH BLAH","phone":"898989"}]

合并两个对象

$scope.object = angular.toJson(angular.merge({}, $scope.usergroup, $scope.addUserJson));

console.log($scope.object);

输出

[{"grpid":"1","username":"Vikram911","firstname":"Vikram","lastname":"Doe","email":"vik@gmail.com","gender":"Male", "description":"BLAH BLAH","phone":"5858585"},{"grpid":"2","username":"Varun091","firstname":"Varun","lastname":"Doe", "email":"varun@gmail.com","gender":"Male","description":"BLAH BLAH","phone":"898989"}]

如何合并上面两个json响应，以便它应该形成如下所示的最终结果

{"username":"Mik911","firstname":"Mike","lastname":"Angel","email":"mik@gmail.com","grpid":["1,2"]}

Answer 1

您不能只将对象与数组合并，也不能只将一个字段合并到合并中。

您可以使用JS数组映射函数在一行中手动设置addUserJson对象的grpid：

$scope.addUserJson.grpid = $scope.usergroup.map(function(grp) { return grp.grpid; });

Answer 2

通过将$scope.addUserJson视为一个数组，我使它更有用......

如果它永远不会是一个数组，请通知我，以便我可以将其更改回单个json对象。

var app = angular.module('myApp',[]);

	app.controller('myCtrl',function($scope){
		
		$scope.usergroup = [{"grpid":"1","username":"Vikram911","firstname":"Vikram","lastname":"Doe","email":"vik@gmail.com","gender":"Male",
		"description":"BLAH BLAH","phone":"5858585"},{"grpid":"2","username":"Varun091","firstname":"Varun","lastname":"Doe",
		"email":"varun@gmail.com","gender":"Male","description":"BLAH BLAH","phone":"898989"}]


		$scope.addUserJson = [{"username":"Mik911","firstname":"Mike","lastname":"Angel","email":"mik@gmail.com"}];
		var result = [];

		// console.log($scope.usergroup);
		for(x in $scope.addUserJson){
			// console.log($scope.addUserJson.username +"=="+ $scope.usergroup[x].username);
			var temp=[];
			for(y in $scope.usergroup){

				if($scope.addUserJson[x].username.localeCompare($scope.usergroup[y].username)){
					temp.push($scope.usergroup[y].grpid);
				}
			}
			if(temp.length>0){
				var result1 = $scope.addUserJson;
				result1[0].grpid = temp;
				result = result1[0];
				temp=[];
			}
		}


		console.log(result);


	});

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<body ng-app="myApp" ng-controller="myCtrl">
</body>

AngularJS合并两个JSON响应

2 个答案: