Question

我正在创建一个具有byte64字符串数据的JSON数组。这是一个无效的JSON，但当我将displaypic值删除一些正常string时，JSON有效。请帮我解决一下这个。有没有其他方法可以处理必须在跨平台上解析的图像。我该如何处理这个字节64字符串。

这是一个很长的数据，因此无法在此处添加..正文限制为30000.请参阅此link了解JSON。

创建JSON的代码

function checkLogin_post()
{
     //$responsedata = array();

    if($this->post('useremail') && $this->post('password'))
    {
        $useremail = $this->post('useremail');
        $password = $this->post('password');


            $this->load->model('loginmodel');

            $table_data = $this->loginmodel->checkLogin($useremail);
            if (sizeof($table_data) != 0)
            {
                foreach ($table_data as $data)
                {
                    if($password == $data->password)
                    {

                        $responsedata["firstname"] = $data->firstname;
                        $responsedata["lastname"] = $data->lastname;
                        $responsedata["email"] = $data->email;
                        $responsedata["userid"] = $data->userid;
                        $responsedata["displaypic"] = $data->displaypic; //THIS IS THE BASE64
                        $responsedata["ispersonaldetailsfilled"] = $data->ispersonaldetailsfilled;
                        $responsedata["isexpertisedetailsfilled"] = $data->isexpertisedetailsfilled;
                        $responsedata["isprofessionaldetailsfilled"] = $data->isprofessionaldetailsfilled;

                        $this->response(array("success"=>$responsedata), 200);
                        //$this->response($responsedata, 200);
                    }
                    else
                    {
                        $this->response(array("error"=>"Password not matched"), 200);
                    }
                }
            }
            else
            {
                $this->response(array("error"=>"User not found"), 200);
            }



    }
    else
    {
        if($this->post('useremail') == "")
            {
                $this->response(array("error"=>"Useremail can't be null"),200);
            }
           if($this->post('password') == "")
            {
                $this->response(array("error"=>"Password can't be null"),200);
            }
    }
}

Answer 1

最后只缺少一个支架。 Here's your corrected JSON

在发布问题之前，始终使用工具验证您的json。我个人喜欢http://pro.jsonlint.com

将base64字符串添加到JSON会使其无效

1 个答案: