Question

新手在这里，我创建了以下查询以从数据库中选择并导出为csv，但我一直收到错误：

$query = "SELECT firstname,lastname,phone,email WHERE firstname = 'Trenton' INTO OUTFILE 'C:/tjtest2.csv' FIELDS TERMINATED BY ',' ENCLOSED BY '\"' LINES TERMINATED BY '\n' FROM students";
$result = mysql_query($query) or die('error'); 
if($result)
{
    echo"yes!";
}
else
{
    echo"NO!";
};

我的可怕的死亡错误不断出现，我无法弄清楚问题在哪里

Answer 1

您需要在条件

之前向学生发送用户

$query = "SELECT firstname,lastname,phone,email form students WHERE firstname = 'Trenton' INTO OUTFILE 'C:/tjtest2.csv' FIELDS TERMINATED BY ',' ENCLOSED BY '\"' LINES TERMINATED BY '\n'";

Answer 2

您将条件置于错误的位置，因此请使用下面的代码 -

$query = "SELECT firstname,lastname,phone,email INTO OUTFILE 'C:/tjtest2.csv' FIELDS TERMINATED BY ',' ENCLOSED BY '\"' LINES TERMINATED BY '\n' FROM students WHERE firstname = 'Trenton'";

<强>更新

通过以下命令获取mysql可以写入的目录路径 -

SHOW VARIABLES LIKE 'secure_file_priv';

它将为您提供类似“C：\ ProgramData \ MySQL \ MySQL Server 5.6 \ Uploads \”的路径，因此请按以下方式使用此路径 -

$query = "SELECT firstname,lastname,phone,email INTO OUTFILE 'C:/ProgramData/MySQL/MySQL Server 5.6/Uploads/tjtest2.csv' FIELDS TERMINATED BY ',' ENCLOSED BY '\"' LINES TERMINATED BY '\n' FROM students WHERE firstname = 'Trenton'";

Answer 3

您是否检查过错误日志以获取确切错误？这个文件已经存在了吗？你也可以在你的其他部分内尝试mysql_error()，记得在测试时删除or die，看看你是否找到了一些关于出错的细节

Answer 4

好的伙计们，我了解到我的查询完全没有问题。问题是我的webhost没有为共享者提供足够高的权限，允许我实现＆＃34; INTO OUTFILE＆＃34;。对于那些拥有足够高权限的人来说，显然这个查询应该有效：

$query = "SELECT record FROM table WHERE variable INTO OUTFILE 'filename.csv' FIELDS TERMINATED BY ',' ENCLOSED BY '\"' LINES TERMINATED BY '\n'"; 
$result = mysql_query($query);
if($result)
{
echo"yes!";
}
else
{
echo mysql_error();
};

将mysql导出到csv时出错

4 个答案: