Question

我正在接受一个句子并将其变成猪拉丁语，但是当我编辑列表中的单词时，它永远不会停留。

sentence = input("Enter a sentence you want to convert to pig latin")

sentence = sentence.split()
for words in sentence:
    if words[0] in "aeiou":
        words = words+'yay'

当我打印句子时，我得到了同样的句子。

Answer 1

因为你没有改变句子

所以要获得你想要的结果

:init

所以现在打印new_sentence

我把它设置为返回一个字符串，如果你想要一个可以轻松完成的列表

new_sentence = ''
for word in sentence:
    if word[0] in "aeiou":
        new_sentence += word +'yay' + ' '
    else:
        new_sentence += word + ' '

如果您正在使用列表，然后想要将列表转换为字符串，那么只需

new_sentence = []
for word in sentence:
    if word[0] in "aeiou":
        new_sentence.append(word + 'yay')
    else:
        new_sentence.append(word)

Answer 2

似乎你没有更新句子。

sentence = input("Enter a sentence you want to convert to pig latin")
sentence = sentence.split()
# lambda and mapping instead of a loop
sentence = list(map(lambda word: word+'yay' if word[0] in 'aeiou' else word, sentence))
# instead of printing a list, print the sentence
sentence = ' '.join(sentence)
print(sentence)

PS。有点忘了关于Python for循环的一些事情所以我没有使用它。遗憾

Answer 3

另一种方法（包括一些修复）

sentence = input("Enter a sentence you want to convert to pig latin: ")

sentence = sentence.split()
for i in range(len(sentence)):
    if sentence[i][0] in "aeiou":
        sentence[i] = sentence[i] + 'yay'
sentence = ' '.join(sentence)

print(sentence)

需要在for循环中编辑列表。 [蟒蛇}

3 个答案: