Twitter API让我通过状态发布推文,但如果我想添加图片则不上传媒体

时间:2016-06-14 20:55:12

标签: ios swift twitter

登录并通过Twitter进行身份验证后,我能够成功地将推文发送到更新网址。

常数......

let kTwitterPOSTmethod = "POST"
let kTwitterUpdateURL = "https://api.twitter.com/1.1/statuses/update.json"
let kTwitterUploadURL = "https://upload.twitter.com/1.1/media/upload.json"

Twitter客户端的东西......

  let store = Twitter.sharedInstance().sessionStore

  if let userid = store.session()?.userID {

    let client = TWTRAPIClient(userID: userid) //from logInWithCompletion() in the previous VC

....

}

当base64Image字符串为"" ...

时,该函数有效
    if snapBase64String == "" {

    //just text (works!)

    var updateParams : [String : AnyObject] = ["status" : withMessage]

        if  let location = currentLocation {

            updateParams = ["status" : withMessage, "lat" : String(Float(location.latitude)), "long" : String(Float(location.longitude))]

    }


    //TODO: Handle error properly (do / catch?)

    let updateRequest = client.URLRequestWithMethod(kTwitterPOSTmethod, URL: kTwitterUpdateURL, parameters: updateParams as [NSObject : AnyObject], error: nil)
    //Lastly, we sent the status update along with the image that we parsed from the earlier request
    client.sendTwitterRequest(updateRequest, completion: { (response, data, connectionError) -> Void in

      if connectionError == nil {
        print("sendTwitterRequest(): \(response)")
        complete(success: true)
      }
      else {
        print("sendTwitterRequest(): \(connectionError)")
        complete(success: false)
      }
    })

    }

包含图像时不起作用的功能。我发布到上传网址并尝试使用JSON序列化程序功能获取media_id_string,但它告诉我我未经授权。

    else {

        let postImageWithStatusRequest = client.URLRequestWithMethod(kTwitterPOSTmethod, URL: kTwitterUploadURL, parameters: ["media": snapBase64String], error: nil)

        client.sendTwitterRequest(postImageWithStatusRequest, completion: { (response, data, error) in

            if error != nil {

                print(error?.localizedDescription)
            }


            if let mediaDict = self.dataToJSON(data!) {

                let message = ["status": withMessage, "media_ids": mediaDict["media_id_string"]]

                let request = client.URLRequestWithMethod(kTwitterPOSTmethod,
                    URL: kTwitterUpdateURL, parameters: message as! [String : AnyObject], error:nil)

                client.sendTwitterRequest(request, completion: { (response, data, connectionError) -> Void in

                    if connectionError == nil {
                        print("sendTwitterRequest(): \(response)")
                        complete(success: true)
                    }
                    else {
                        print("sendTwitterRequest(): \(connectionError)")
                        complete(success: false)
                    }


                })
            }
        })

    }

JSON转换功能

class func dataToJSON(data: NSData) -> AnyObject? {

    do {
        return try NSJSONSerialization.JSONObjectWithData(data, options: .MutableContainers)
    } catch let myJSONError {
        print(myJSONError)
    }
    return nil
}

我得到的错误消息...我是否需要不同的身份验证才能发布到服务器的上传部分?我不确定为什么它会让我发布状态,但是当我想发布媒体时它不起作用。

  

▿可选     - 一些:错误域= TwitterAPIErrorDomain代码= 32"请求失败:未授权(401)"   的UserInfo = {NSErrorFailingURLKey = https://upload.twitter.com/1.1/media/upload.json,   NSLocalizedDescription =请求失败:未授权(401),   NSLocalizedFailureReason = Twitter API错误:无法进行身份验证   您。 (代码32)}

感谢您的帮助!

2 个答案:

答案 0 :(得分:0)

我弄清楚了,它与身份验证无关,错误非常具有误导性。

我所做的是改变我编码base 64字符串的方式。我只是将选项设置为空而不是64CharacterLineLength而且它有效!

let base64String = mapSnapData.base64EncodedStringWithOptions([])
snapBase64String = base64String

答案 1 :(得分:0)

以下是我的工作代码。

func shareToTwitter(){


    let store = Twitter.sharedInstance().sessionStore
    if let userid = store.session()?.userID {
        let client = TWTRAPIClient(userID: userid)
        let statusesShowEndpoint = "https://upload.twitter.com/1.1/media/upload.json"

        let image = UIImage(named: "How_To_Say_TY")
        let data = UIImagePNGRepresentation(image!)
        let strImage = data?.base64EncodedStringWithOptions([])

        let params  : [String : AnyObject] = ["media": strImage!]
        var clientError : NSError?

        let request = client.URLRequestWithMethod("POST", URL: statusesShowEndpoint, parameters: params, error: &clientError)

        client.sendTwitterRequest(request) { (response, data, connectionError) -> Void in

            if (connectionError == nil) {

                do {
                    let json = try NSJSONSerialization.JSONObjectWithData(data!, options: .AllowFragments)
                    print("test tweet :- \(json["media_id_string"])")

                    self.updateTwitterStatusWithMediaID("\(json["media_id_string"])")

                } catch {
                    print("error serializing JSON: \(error)")
                }
            }
            else {
                print("Error: \(connectionError)")
            }
        }
    }
}

func updateTwitterStatusWithMediaID( mediaID : String ){

    let store = Twitter.sharedInstance().sessionStore
    if let userid = store.session()?.userID {
        let client = TWTRAPIClient(userID: userid)
        let statusesShowEndpoint = "https://api.twitter.com/1.1/statuses/update.json"
        let params = ["status": "Test by Carl.","media_ids":mediaID]
        var clientError : NSError?

        let request = client.URLRequestWithMethod("POST", URL: statusesShowEndpoint, parameters: params, error: &clientError)

        client.sendTwitterRequest(request) { (response, data, connectionError) -> Void in

            if (connectionError == nil) {

                do {
                    let json = try NSJSONSerialization.JSONObjectWithData(data!, options: .AllowFragments)
                    print("test tweet :- \(json)")
                } catch {
                    print("error serializing JSON: \(error)")
                }
            }
            else {
                print("Error: \(connectionError)")
            }
        }
    }
}