Question

我有一个XML文件

<?xml version="1.0" encoding="utf-8" standalone="no"?>
<File>
    <Cars>
        <Car>
            <Color>Blue</Color>
            <Year>1988</Year>
        </Car>
        <Car>
            <Color>Green</Color>
            <Year>1989</Year>
        </Car>
        <Car>
            <Color>Yellow</Color>
            <Year>1989</Year>
        </Car>
    </Cars>
</File>

我想用这个对象在这个文件上创建一个过滤器：

public class condition
{
    public string color { get; set; }

    public string year { get; set; }
}

List<condition> c = new List<condition>
{
    new condition()
    {
        color = "Green",
        year = "1989"
    },
    new condition()
    {
        color = "Blue",
        year = "1988"
    }
};

我想只带(color = Green and year = 1989) OR (color = blue and year = 1988)

的车

但我不知道如何做到这一点。也许使用XDocument和Linq.Dynamic？

Answer 1

您可以使用XDocument轻松过滤linq中的xml。此函数将使用Remove()扩展方法基于过滤器删除所有节点。

private void RemoveCars(string color, string year)
{
  var doc = XDocument.Load("<myxml>...</myxml>");
  doc.Element("File")
     .Element("Cars")
     .Elements("Cars")
     .Where(c=> c.Element("color").Value == color
                && c.Element("Year").Value == year)
     .Remove();

  doc.Save("c:\\mypath\\my.xml");

}

Answer 2

您可以使用Linq to xml的另一个选项

import UIKit

class MyTableViewController: UITableViewController {

    override func viewDidLoad() {
        super.viewDidLoad()
        self.refreshControl?.enabled = true
        self.refreshControl?.userInteractionEnabled = true
        print("MyTableViewController",self.refreshControl!, self.refreshControl?.enabled)
    }

    override func didReceiveMemoryWarning() {
        super.didReceiveMemoryWarning()
    }

    func refresh(sender:AnyObject) {
        // Code to refresh table view
        print("Refresing contents...")

        self.refreshControl?.endRefreshing()
    }   
}

过滤xml文件

2 个答案: