Question

我有3个表，需要从1-st中选择记录然后将记录插入到2-nd，最后将记录插入到3-rd

CREATE TABLE public.t_sender (
  id BIGINT PRIMARY KEY NOT NULL DEFAULT nextval('t_sender_id_seq'::regclass),
  soft_id SMALLINT NOT NULL,
  sender_model_id SMALLINT NOT NULL,
);

CREATE TABLE public.t_receiver (
  id BIGINT PRIMARY KEY NOT NULL DEFAULT nextval('t_receiver_id_seq'::regclass),
  receiver_owner_id BIGINT,
  );

CREATE TABLE public.t_sender_to_receiver (
  id BIGINT PRIMARY KEY NOT NULL DEFAULT nextval('t_sender_to_receiver_id_seq'::regclass),
  sender_id BIGINT NOT NULL,
  receiver_id BIGINT NOT NULL,
  FOREIGN KEY (sender_id) REFERENCES public.t_sender (id)
  MATCH SIMPLE ON UPDATE RESTRICT ON DELETE RESTRICT,
  FOREIGN KEY (receiver_id) REFERENCES public.t_receiver (id)
  MATCH SIMPLE ON UPDATE RESTRICT ON DELETE RESTRICT
);

我从第一张表中获取了ID值

CREATE OR REPLACE FUNCTION selectreceiverWithoutsender(user_id_param bigint) 
    RETURNS setof bigint AS $BODY$
    SELECT id FROM t_receiver WHERE id in (SELECT receiver_id FROM t_user_to_receiver WHERE user_id_param=$1) AND id NOT IN (SELECT receiver_id FROM t_sender_to_receiver);
$BODY$ LANGUAGE plpgsql;

然后插入第2和第3个表

CREATE OR REPLACE FUNCTION insertSendersForUserId(user_id_param bigint)
    RETURNS void AS $BODY$
BEGIN
        WITH insSender AS (insert into t_sender(sender_status, soft_id) select 1,0  from selectReceiverWithoutSender($1) RETURNING id)
        INSERT INTO t_sender_to_receiver(receiver_id, sender_id) VALUES ((selectReceiverWithoutSender($1)), (select id from insSender) );
END;
$BODY$ LANGUAGE plpgsql;

我的问题是我从第一个插入 insSender 中获取了多个ID值，并在我尝试执行功能时出现下一个错误：

DO $$
BEGIN
    select 1 from insertDadsForUserId(44);
END
$$ LANGUAGE plpgsql;

由用作表达式的子查询返回的多行 SQL状态：21000 上下文：SQL语句＆＃34; WITH insSender AS（插入到t_sender ...

那么如何准备这个值以插入下一个插入？

对不起，如果这不是一个非常困难的问题，我第一次体验了PostgresSQL的功能，并没有在互联网上提供解决方案。

PostgreSQL的。如何从另一个插入插入值？

0 个答案: