嘿伙计们:我真的被困在这个。
我有一个使用REST服务的grails应用程序。 它适用于访问REST服务,但问题是当我想在GSP中呈现结果时。我收到以下错误:
errors.GrailsExceptionResolver - NullPointerException occurred when processing request: [GET] /TestAPI/login/index
Stacktrace follows:
java.lang.NullPointerException
at grails.plugin.cache.web.filter.PageFragmentCachingFilter.doFilter(PageFragmentCachingFilter.java:198)
at grails.plugin.cache.web.filter.AbstractFilter.doFilter(AbstractFilter.java:63)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1142)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:617)
at java.lang.Thread.run(Thread.java:745)
以下是我的问题: 1.我试图将输出发送到不同的GSP而不是索引。 2.我读了堆栈跟踪,在我的项目中,我在该路径中有index.gsp,它说它无法找到。
这是我的控制器代码:
package testapi
import org.springframework.http.HttpEntity
import org.springframework.http.HttpHeaders
import org.springframework.http.client.support.HttpAccessor
import org.springframework.web.client.RestTemplate
import org.springframework.http.HttpMethod;
import org.springframework.stereotype.Component;
import groovyx.net.http.*
import java.util.Base64;
import java.util.Map;
//import org.springframework.web.client.RestTemplate;
class LoginController {
def index()
{
String usernm = "xxxxxxxxxx";
String link = "https://xxx.xxx.xxx/oauth2/token";
String passwd = "yyyyyy";
//Base64.encodeBase64(usernm.concat(":".concat(passwd)).getBytes())
Base64.getEncoder().encode(usernm.concat(":".concat(passwd)).getBytes());
String base64UserCreds = new String(Base64.getEncoder().encode(usernm.concat(":".concat(passwd)).getBytes()));
RestTemplate restTemplate = new RestTemplate();
HttpHeaders requestHeaders = new HttpHeaders();
requestHeaders.add("Authorization","Basic ".concat(base64UserCreds));
HttpEntity<String> request = new HttpEntity<>(requestHeaders);
System.out.println ("URI under Test is: " + String.valueOf(link) + ". \n" + "Please stand by for results ... \n \n ");
System.out.println ("Base 64 encoded string is: " + base64UserCreds);
@SuppressWarnings("rawtypes")
Map result = restTemplate.exchange(link, HttpMethod.POST, request, Map.class).getBody();
String authtype = (String) result.get("tokenType");
String tokenaccess = (String) result.get("accessToken");
//PrintStream testOutput = null;
//testOutput.append(result2);
System.out.println("Access token: " + tokenaccess + "\n");
HttpHeaders requestHeaders2 = new HttpHeaders();
requestHeaders2.add("zzzz-pppp-oauth-scope", "zzz:read-any");
requestHeaders2.add("Authorization","Bearer ".concat(tokenaccess));
HttpEntity<String> request2 = new HttpEntity<>(requestHeaders2);
System.out.println("URI #1 under test: https://xxxx.xxxx.xxxx?expand=reps \n");
String result3 = restTemplate.exchange("https://xxxx.xxxx.xxxx?expand=reps", HttpMethod.GET, request2, String.class).getBody();
[result3]
render(view: "api_test", model:[name: result3])
System.out.println(result3);
}
}
这是gsp:
<%@ page contentType="text/html;charset=UTF-8" %>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8"/>
<meta name="layout" content="main"/>
<title>AutoTest - API</title>
</head>
<body>
<div class="body">
API Results ${result3}
</div>
</body>
</html>
注意:我没有域类文件;如果是的话,我是否需要一个 - 请告诉我如何构建它。
感谢。
注意:添加项目目录结构的图片:
答案 0 :(得分:1)
渲染result3不会渲染视图而是渲染result3的内容,所以json响应并不奇怪。
如果您可以使用来自&#39; grails-app&#39;的目录发布您的文件名。我们可能会看到问题(例如&#39; /grails-app/views/login/api_test.gsp')