Xcode 10.1 Swift 4

Question

你好我有工作json解析swift2.2的代码，但是当我用它为Swift 3.0给我错误

ViewController.swift：132：31：对成员＆＃39; dataTask的不明确引用（with：completionHandler：）＆＃39;

我的代码在这里

   let listUrlString =  "http://bla.com?batchSize=" + String(batchSize) + "&fromIndex=" + String(fromIndex)
    let myUrl = URL(string: listUrlString);
    let request = NSMutableURLRequest(url:myUrl!);
    request.httpMethod = "GET";

    let task = URLSession.shared().dataTask(with: request) {
        data, response, error in

        if error != nil {
            print(error!.localizedDescription)
            DispatchQueue.main.sync(execute: {
                AWLoader.hide()
            })

            return
        }

        do {

            let json = try JSONSerialization.jsonObject(with: data!, options: .mutableContainers) as? NSArray

            if let parseJSON = json {

                var items = self.categoryList

                items.append(contentsOf: parseJSON as! [String])

                if self.fromIndex < items.count {

                    self.categoryList = items
                    self.fromIndex = items.count

                    DispatchQueue.main.async(execute: {

                        self.categoriesTableView.reloadData()

                        AWLoader.hide()

                    })
                }else if( self.fromIndex == items.count){


                    DispatchQueue.main.async(execute: {

                        AWLoader.hide()

                    })

                }



            }

        } catch {
            AWLoader.hide()
            print(error)

        }
    }

    task.resume()

感谢您的想法。

Answer 1

编译器被函数签名搞糊涂了。你可以像这样解决它：

let task = URLSession.shared.dataTask(with: request as URLRequest) {

但是，请注意，我们不必投出＆＃34;请求＆＃34;作为此签名中的URLRequest，如果之前已将其声明为URLRequest而不是NSMutableURLRequest：

var request = URLRequest(url:myUrl!)

这是NSMutableURLRequest与失败的新URLRequest之间的自动投射，迫使我们在此处进行投射。

Answer 2

您已将myRequest初始化为NSMutableURLRequest，您需要：

var URLRequest

斯威夫特放弃了NSMutable...这件事。只需使用var作为新类。

Answer 3

Xcode 8和Swift 3.0

使用网址：

 let url = URL(string:"Download URL")!
 let req = NSMutableURLRequest(url:url)
 let config = URLSessionConfiguration.default
 let session = URLSession(configuration: config, delegate: self, delegateQueue: OperationQueue.main)

 let task : URLSessionDownloadTask = session.downloadTask(with: req as URLRequest)
task.resume()

URLSession委托电话：

func urlSession(_ session: URLSession, task: URLSessionTask, didCompleteWithError error: Error?) {

}


func urlSession(_ session: URLSession, downloadTask: URLSessionDownloadTask, 
didWriteData bytesWritten: Int64, totalBytesWritten writ: Int64, totalBytesExpectedToWrite exp: Int64) {
                   print("downloaded \(100*writ/exp)" as AnyObject)

}

func urlSession(_ session: URLSession, downloadTask: URLSessionDownloadTask, didFinishDownloadingTo location: URL){

}

使用Block GET / POST / PUT / DELETE：

 let request = NSMutableURLRequest(url: URL(string: "Your API URL here" ,param: param))!,
        cachePolicy: .useProtocolCachePolicy,
        timeoutInterval:"Your request timeout time in Seconds")
    request.httpMethod = "GET"
    request.allHTTPHeaderFields = headers as? [String : String] 

    let session = URLSession.shared

    let dataTask = session.dataTask(with: request as URLRequest) {data,response,error in
        let httpResponse = response as? HTTPURLResponse

        if (error != nil) {
         print(error)
         } else {
         print(httpResponse)
         }

        DispatchQueue.main.async {
           //Update your UI here
        }

    }
    dataTask.resume()

为我工作正常..试试100％结果保证

Answer 4

这个问题是由URLSession引起的，有两个dataTask方法

open func dataTask(with request: URLRequest, completionHandler: @escaping (Data?, URLResponse?, Error?) -> Swift.Void) -> URLSessionDataTask
open func dataTask(with url: URL, completionHandler: @escaping (Data?, URLResponse?, Error?) -> Swift.Void) -> URLSessionDataTask

第一个有URLRequest作为参数，第二个有URL作为参数，所以我们需要指定要调用的类型，例如，我想调用第二个方法

let task = URLSession.shared.dataTask(with: url! as URL) {
    data, response, error in
    // Handler
}

Answer 5

在我的情况下，错误出现在 NSURL

中

let url = NSURL(string: urlString)

在Swift 3中，您必须只写网址：

let url = URL(string: urlString)

Answer 6

经过测试的xcode 8稳定版; 需要将var request变量与URLRequest()一起使用你可以轻松修复它（ bug ）

var request = URLRequest(url:myUrl!)和

let task = URLSession.shared().dataTask(with: request as URLRequest) { }

工作得很好！谢谢你们，我想帮助很多人。！

Answer 7

对于Swift 3和Xcode 8：

      var dataTask: URLSessionDataTask?

      if  let url = URL(string: urlString) {
            self.dataTask = URLSession.shared.dataTask(with: url, completionHandler: { (data, response, error) in

                if let error = error {
                    print(error.localizedDescription)
                } else if let httpResponse = response as? HTTPURLResponse, httpResponse.statusCode == 200 {
                     // You can use data received.
                    self.process(data: data as Data?)
                }
            })
        }
     }

//注意：您始终可以使用调试器来检查错误

Answer 8

在swift 3中，编译器被函数签名所困惑。指定它将清除错误。还要将url字符串转换为URL类型。以下代码对我有用。

   let urlString = "http://bla.com?batchSize="
   let pathURL = URL(string: urlString)!
   var urlRequest = URLRequest(url:pathURL)

    let session = URLSession.shared
    let dataTask = session.dataTask(with: urlRequest as URLRequest) { (data,response,error) in

Answer 9

Swift 3的简短回答：

guard let requestUrl = URL(string: yourURL) else { return }

let request = URLRequest(url:requestUrl)
URLSession.shared.dataTask(with: request) {
    (data, response, error) in
    ...

}.resume()

Answer 10

 // prepare json data
        let mapDict = [ "1":"First", "2":"Second"]

        let json = [ "title":"ABC" , "dict": mapDict ] as [String : Any]
        let jsonData : NSData = NSKeyedArchiver.archivedData(withRootObject: json) as NSData

        // create post request
        let url = NSURL(string: "http://httpbin.org/post")!
        let request = NSMutableURLRequest(url: url as URL)
        request.httpMethod = "POST"

        // insert json data to the request
        request.httpBody = jsonData as Data


        let task = URLSession.shared.dataTask(with: request as URLRequest){ data,response,error in
            if error != nil{
                return
            }
            do {
                let result = try JSONSerialization.jsonObject(with: data!, options: []) as? [String:AnyObject]

                print("Result",result!)

            } catch {
                print("Error -> \(error)")
            }
        }

        task.resume()

Answer 11

要通过GET请求加载数据，您不需要任何URLRequest（并且没有分号）

let listUrlString =  "http://bla.com?batchSize=" + String(batchSize) + "&fromIndex=" + String(fromIndex)
let myUrl = URL(string: listUrlString)!
let task = URLSession.shared.dataTask(with: myUrl) { ...

Answer 12

let task = URLSession.shared.dataTask(with: request as URLRequest, completionHandler: { data,response,error in
        if error != nil{
            print(error!.localizedDescription)
            return
        }
        if let responseJSON = (try? JSONSerialization.jsonObject(with: data!, options: [])) as? [String:AnyObject]{
            if let response_token:String = responseJSON["token"] as? String {
                print("Singleton Firebase Token : \(response_token)")
                completion(response_token)
            }
        }
    })
    task.resume()

Answer 13

对我来说，我这样做是为了找到，

let url = URL(string: urlString)
URLSession.shared.dataTask(with: url!) { (data, response, error) in ...}

无法使用

"let url = NSURL(string: urlString)

Answer 14

Xcode 10.1 Swift 4

这对我有用：

let task: URLSessionDataTask = session.dataTask(with: request as URLRequest) { (data, response, error) -> Void in
...

密钥已添加到URLSessionDataTask类型声明中。

Swift 3 URLSession.shared（）对成员＆＃39; dataTask的不明确引用（with：completionHandler :)错误（bug）

14 个答案:

Xcode 10.1 Swift 4