排序自定义类字典C#

时间:2016-06-14 11:58:37

标签: c# sorting dictionary

我有一个嵌套的公共类KeyCountMap

public KeyCountMap<T>  
{ 
   private IDictionary<T, MutableInt> map = new Dictionary<T, MutableInt>();
   public KeyCountMap()
   { }

   public KeyCountMap(Type dictionaryType)
   {
      if (!typeof(IDictionary<T, MutableInt>).IsAssignableFrom(dictionaryType))
      {
         throw new ArgumentException("Type must be a IDictionary<T, MutableInt>", "dictionaryType");
      }
      map = (IDictionary<T, MutableInt>)Activator.CreateInstance(_dictionaryType);
   }  

   public HashSet<KeyValuePair<T, MutableInt>> EntrySet()
   {
      return map.ToSet();
   }  
   //... rest of the methods...
}

要按值的降序排序map中的值,如果我们使用Java,我们可以将方法编写为:

public static <T> KeyCountMap<T> sortMapByDescendValue(KeyCountMap<T> map) 
{
   List<Entry<T, MutableInt>> list = new LinkedList<>(map.entrySet());
   Collections.sort(list, new Comparator<Entry<T, MutableInt>>() 
   {
      @Override
      public int compare(Entry<T, MutableInt> o1, Entry<T, MutableInt> o2)  
      {
         return (-1) * (o1.getValue().get()).compareTo(o2.getValue().get());
      }
   });

   KeyCountMap<T> result = new KeyCountMap<T>();
   for (Entry<T, MutableInt> entry : list) 
   {
      result.put(entry.getKey(), entry.getValue());
   }
   return result;
}

如果我们使用C#,我们可以将方法定义为:

public static KeyCountMap<T> SortMapByDescendValue<T>(KeyCountMap<T> map)
{
   List<KeyValuePair<T, MutableInt>> list = new List<KeyValuePair<T, MutableInt>>(map.EntrySet());  
   // map.EntrySet() returns of type HashSet<KeyValuePair<T, MutableInt>>  

   list = list.OrderByDescending(x => x.Value).ToList();

   KeyCountMap<T> result = new KeyCountMap<T>();
   foreach (KeyValuePair<T, MutableInt> entry in list)
   {
      result.Put(entry.Key, entry.Value);

   }
   return result; 
}

此方法是否有效或是否需要覆盖CompareTo()方法(此处未使用)进行排序?

编辑

public class MutableInt
{
   internal int _value = 1; // note that we start at 1 since we're counting

   public void Increment()
   {
      _value++;
   }

   public void Discrement()
   {
      _value--;
   }

   public int Get()
   {
      return _value;
   }
}

2 个答案:

答案 0 :(得分:2)

字典(哈希表)没有订单。尝试通过控制插入顺序来订购哈希集只是不起作用。如果您想订购,请不要使用字典作为后备商店。

答案 1 :(得分:0)

如果您想要永久排序字典,可以尝试使用SortedDictionary<K,V>实现排序:

  // Please, notice ...map => new... (C# 6.0 syntax) 
  // since you can't address map in the initializator (=)
  private IDictionary<T, MutableInt> map => new SortedDictionary<T, MutableInt>(
    // You are supposed to compare keys
    Comparer<T>.Create((leftKey, rightKey) => {
      // given keys, get values
      MutableInt left = map[leftKey]; 
      MutableInt right = map[rightKey];  

      //TODO: you may want to change logic here
      // you should return any positive integer if left > right
      // negative integer if left < right
      // zero in case left == right
      // current implementation (CompareTo) assumes that 
      // MutableInt implements IComparable<MutableInt> interface
      return -left.CompareTo(right);
    })
  );

编辑:如果你想代表按价值排序的字典,最好的方法是恕我直言,使值可比较

public class MutableInt: IComparable<MutableInt> 
{
  ...
  public int CompareTo(MutableInt other) 
  {
    return (null == other)
      ? 1
      : _value.CompareTo(other._value);      
  } 
  ...
}

然后使用 Linq

//Notice, that you can't return sorted values as dictionary
public static IEnumerable<KeyValuePair<T, MutableInt>> SortMapByDescendValue<T>(
  KeyCountMap<T> map)
{
   return map
     .OrderByDescending(pair => pair.Value); // Value is comparable now
}

你唯一不能做的就是排序标准字典(Dictionary<K, V>