stdout pymssql变量

时间:2016-06-14 10:49:34

标签: python linux execute pymssql

我试图检索运行

的结果表单
import pymssql
conn = pymssql.connect(server='IP', user='domain\user', password='PSWD', tds_version='8.0')
cursor = conn.cursor()
cursor.execute("EXEC msdb.dbo.sp_start_job @job_name = 'jobname'")

当它将作业添加到cue进行处理时它不会返回任何内容,但是当作业没有运行时它会返回类似于测试的内容

Traceback (most recent call last):
  File "shared/python3", line 85, in <module>
    cursor.execute("EXEC msdb.dbo.sp_start_job @job_name = ''")
  File "pymssql.pyx", line 467, in pymssql.Cursor.execute (pymssql.c:7533)
pymssql.OperationalError: (14262, "The specified @job_name ('') does not exist.DB-Lib error message 14262, severity 16:\nGeneral SQL Server error: Check messages from the SQL Server\n")

在这种情况下,错误指出Job_name不存在。我想要做的是将结果放在一个字符串变量上,我可以将其解析为错误控制......

我试过这个:

import sys

# Store the reference, in case you want to show things again in standard output
old_stdout = sys.stdout

# This variable will store everything that is sent to the standard output
result = StringIO()
sys.stdout = result

# Here we can call anything we like, like external modules, and everything that they will send to standard output will be stored on "result"
cursor.execute("EXEC msdb.dbo.sp_start_job @job_name = 'jobname'")

# Redirect again the std output to screen
sys.stdout = old_stdout

# Then, get the stdout like a string and process it!
result_string = result.getvalue()
process_string(result_string)

link。但无法让它发挥作用。

1 个答案:

答案 0 :(得分:2)

您正在查看回溯,因为您没有处理作业名称不存在时发生的异常。如果要捕获错误消息,只需捕获异常即可。作为一个通用的例子,而不仅仅是做

crsr.execute(sql)

你可以做到

try:
    crsr.execute(sql)
except Exception as e:
    (error_code, error_message) = e

然后使用error_codeerror_message值将它们写入日志文件,或将它们吐出到控制台或其他任何内容。